Any value between 0 and 360 degrees. Perhaps excluding 180 degrees since that is just a straight line.
42
The sum of interior angles of a polygon with 'n' sides = 180( n - 2 ) degrees Replace n with 32 We get 5400 degrees.
To find the interior angle of a 34-sided polygon, you can use the formula for the interior angle, which is ((n - 2) \times 180^\circ / n), where (n) is the number of sides. For a 34-sided polygon, the calculation is ((34 - 2) \times 180^\circ / 34), resulting in ((32 \times 180^\circ) / 34), which equals approximately 169.41 degrees. Thus, the interior angle of a 34-sided shape is about 169.41 degrees.
They add up to 5400 degrees
Providing that it is a regular polygon then let its sides be x: So: 0.5*(x2-3x) = 464 diagonals Then: x2-3x-928 = 0 Solving the equation: x = 32 sides Total sum of interior angles: 30*180 = 5400 degrees Each interior angle: (5400+360)/180 = 168.75 degrees
gghg a regular polygon has a 32 sides. calculate the size of each interior angle.
42
The exterior angle is 360/32 = 11.25 Therefore the interior angle is 180 - 11.25 = 168.75
The sum of interior angles of a polygon with 'n' sides = 180( n - 2 ) degrees Replace n with 32 We get 5400 degrees.
As in the question it is 5400 degrees. But a polygon whose interior angles add up to 5400 degrees will have 32 sides
Interior angle = 180*(n-2)/2 So it would be 180*32/34 Times that answer by 34 and you get 5760.
Each exterior angle measures 11.5 degrees. Each interior angle measures 168.75 degrees
It has 32 sides and each interior angle measures 168.75 degrees and so 180-168.75 = 11.25 degrees which is the measure of each exterior angle
To find the interior angle of a 34-sided polygon, you can use the formula for the interior angle, which is ((n - 2) \times 180^\circ / n), where (n) is the number of sides. For a 34-sided polygon, the calculation is ((34 - 2) \times 180^\circ / 34), resulting in ((32 \times 180^\circ) / 34), which equals approximately 169.41 degrees. Thus, the interior angle of a 34-sided shape is about 169.41 degrees.
In general, this question cannot be answered. Any polygon can have an interior angle of 108 degrees. For example, a triangle with angles of 108, 32 and 40 degrees; or a quadrilateral with angles of 108, 72, 90 and 90 degrees and so on.In the rare event that the polygon is a regular polygon, then suppose it has n sides.The sum of its interior angles is then (n-2)*180 degreesSo that each interior angle is (n-2)*180/n degrees.Thus (n-2)*180/n = 108(n-2)*180 = 108*n180n - 360 = 108n72n = 360n = 5 sides.
The measure of the exterior angle of a 11-sided polygon = 360⁰/11 = 32 72/99⁰ = 32 8/11⁰
A 32-sided shape is called a "triacontadigon." It is a polygon with 32 sides and 32 angles. The name is derived from the Greek prefixes "triaconta-" for thirty and "-gon" for angle or side.