Maximum = 45 Minimum = 14 Range = Max - min = 45 - 14 = 31
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
To find the maximum, minimum, range, and median of the numbers 28, 17, 45, 32, 29, 28, 14, and 27: The maximum is 45, and the minimum is 14. The range is calculated as maximum minus minimum, which is 45 - 14 = 31. To find the median, we first sort the numbers: 14, 17, 27, 28, 28, 29, 32, 45. Since there are 8 numbers, the median is the average of the 4th and 5th numbers: (28 + 28)/2 = 28.
The range of the given numbers is 14. To find the range, subtract the smallest number from the largest number in the set. In this case, the largest number is 39 and the smallest number is 25, so the range is 39 - 25 = 14.
14/29 cannot be simplified
14
Maximum = 45 Minimum = 14 Range = Max - min = 45 - 14 = 31
Which equation can have the following domain and range? {x | 8 ≤ x ≤ 14} {y | 29 ≤ y ≤ 53}Answer this question…
To find the maximum, minimum, range, and median of the numbers 28, 17, 45, 32, 29, 28, 14, and 27: The maximum is 45, and the minimum is 14. The range is calculated as maximum minus minimum, which is 45 - 14 = 31. To find the median, we first sort the numbers: 14, 17, 27, 28, 28, 29, 32, 45. Since there are 8 numbers, the median is the average of the 4th and 5th numbers: (28 + 28)/2 = 28.
It is: 29*14 = 406
14 out of 29 = 48.3%
The range of the given numbers is 14. To find the range, subtract the smallest number from the largest number in the set. In this case, the largest number is 39 and the smallest number is 25, so the range is 39 - 25 = 14.
Difference means minus the two numbersie. 29 - 14 = 15This means that the difference is 15.
the sum of -14 + 29 is 15
14/29 cannot be simplified
29
The whole number division of 29 by 14 results in a quotient of 2 with a remainder of 1. Therefore, 14 goes into 29 two times with a remainder of 1.