√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
2 root 3x
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
3x y^3
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
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√(24x)4/√(3x) = [242x2√(3x)]/3x = 8(24)x√(3x) = 192x√(3x)
No. The Square root of x is not the value of x. So it can not be simplified beyond: Root X + root 3x Yes. The square root of 3x equals the square root of 3 times the square root of x, so when you add another square root of x, you can factor out the square root of x, thereby simplifying the expression to the square root of x times the sum of one plus the square root of three.
2 root 3x
It is: 3x
the answer of √8x+16-3x=0 is x= 0.447213595 = +/- 0.447(to 3 decimal places) if I'm not mistaken
Sqrt(24x4)/Sqrt(3x) = Sqrt(24x4/3x) = Sqrt(8x3) = Sqrt(4x2*2x) = 2x*sqrt(2x)
x2 + 3x + 9 has no real solutions. Applying the quadratic formula, we get two imaginary solutions: (negative three plus or minus three i times the square root of three) divided by two.x = -1.5 + 2.598076211353316ix = -1.5 - 2.598076211353316iwhere i is the square root of negative one.
2x2 - 3x + 7 = 0 doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: (3 plus or minus the square root of -47) divided by 4.x = 0.75 + 1.713913650100261ix = 0.75 - 1.713913650100261iwhere i is the square root of negative 1
3x y^3
x2 + 3x + 3 = 0 doesn't factor neatly. Applying the quadratic formula we find two imaginary solutions: (-3 plus or minus the square root of -3) divided by 2x = -1.5 + 0.8660254037844386ix = -1.5 - 0.8660254037844386iwhere i is the square root of negative 1