130, 260,390,520,650,780,910.1040.
So the largest three digit number with factors of '5' & '13' is 910.
No. Consider 13 or 23.
936. All numbers divisible by 12 and 13 are multiplies of the lowest common multiple of 12 and 13 which is 156. 999 ÷ 156 = 621/52 ⇒ greatest multiple of 156 not bigger than 999 is 6 x 156 = 936.
-70
A number is divisible by 13 if it is a multiple of 13. In other words, 13 times a number results in a big number that is divisible by 13.
There is no answer to this question. No matter what big number one comes up with, it can be multiplied by 13 to make an even bigger number.
975
No. Consider 13 or 23.
104
936. All numbers divisible by 12 and 13 are multiplies of the lowest common multiple of 12 and 13 which is 156. 999 ÷ 156 = 621/52 ⇒ greatest multiple of 156 not bigger than 999 is 6 x 156 = 936.
-70
A number is divisible by 13 if it is a multiple of 13. In other words, 13 times a number results in a big number that is divisible by 13.
There is no answer to this question. No matter what big number one comes up with, it can be multiplied by 13 to make an even bigger number.
-10
No. All multiples of 8 are even, but 141 is odd, so 141 is not divisible by 8. ------------------------------------------ To test if a number is divisible by 8, add 4 times the hundreds digit to 2 times the tens digit to the ones digit; if this sum is divisible by 8, then so is the original number. The test can be repeated on the sum, so continue the summing process until a single digit remains - only if this single digit is an 8 is the original number divisible by 8. 141 → 4 × 1 + 2 × 4 + 1 × 1 = 13 13→ 4 × 0 + 2 × 1 + 3 = 5 5 is not 8, so 141 is not divisible by 8 141 ÷ 8 has a remainder of 5.
Starting with 104 (which is 8 x 13), then 117, 130, 143, 156, . . . . , 962, 975, & 988.
13
13 and all its multiples are divisible by 13.