There is none. Since numbers don't stop, multiples don't stop either.
There is no largest common multiple of any set of numbers as whatever value is assumed to be the largest can be increased by adding the lowest common multiple of the numbers to get an even larger common multiple. For 2 and 3 the lowest common multiple is 6. So whatever number is assumed to be the largest common multiple it can always be increased by 6 to get a larger common multiple.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
The greatest common multiple of 10 and 18 is infinite.However, I suspect you want either:the greatest common factor of 10 and 18 which is the largest number which divides both 10 and 18 and is 2; orthe lowest common multiple of 10 and 18 which is smallest number into which both 10 and 18 divide (ie the smallest number which is a multiple of both 10 and 18) and is 90
It will be the largest multiple of 60
1 is the least common factor of the number 2, number 4 and number 7. 28 is the least common multiple of the number 2, number 4 and 7.
There is no largest common multiple of any set of numbers as whatever value is assumed to be the largest can be increased by adding the lowest common multiple of the numbers to get an even larger common multiple. For 2 and 3 the lowest common multiple is 6. So whatever number is assumed to be the largest common multiple it can always be increased by 6 to get a larger common multiple.
There is no largest common multiple of any two numbers: whatever common multiple is claimed to be the largest can be increased to an even larger common multiple by adding the lowest common multiple for the numbers (which for 2 and 3 is 6).
That doesn't exist. There is no multiple of 6 so large that you can't add 6 to it.
You normally calculate the "least common multiple" for two or more numbers - not for a single number. The "least common multiple" of a single number, of course, is the number itself. Not much calculation involved there. Also, the "least common multiple" of several numbers must be at least as large as the largest of the numbers.
Start by factoring each number completely.14 = 2 × 736 = 2 × 2 × 3 × 328 = 2 × 2 × 7Now write each number in exponential form.14 = 21 × 7136 = 22 × 3228 = 22 × 71Since we are looking for the smallest multiple common to all three of the given numbers, multiply together the largest power of each prime shown.The largest power of 2 shown is 22.The largest power of 3 shown is 32.The largest power of 7 shown is 71.So, the least common multiple is 22 × 32 × 71 = 252.
No, in order for the number to be even, the last number must be a multiple of 2. It doesn't matter what the largest number is as long as the last number is a multiple of two.
The greatest common multiple of 10 and 18 is infinite.However, I suspect you want either:the greatest common factor of 10 and 18 which is the largest number which divides both 10 and 18 and is 2; orthe lowest common multiple of 10 and 18 which is smallest number into which both 10 and 18 divide (ie the smallest number which is a multiple of both 10 and 18) and is 90
It will be the largest multiple of 60
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.
The LCM (Least Common Multiple of 7 and 2) is 14.
10
Yes, if it is a multiple of the smaller number.