It can be infinitely large.
Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm.
Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2.
Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm
or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm
or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm
By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
88mm squared
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
== 25x25== 625 Rectangle sides 5 cm each. ==
The dimensions of the rectangle are 3 inches by 14 inches
perimeter = (5+5+12+12)= 34 area = (5*12) = 60 squared
Oh, what a lovely question! To find the area of a rectangle, you simply need to multiply the length by the width. Since we know the perimeter is 72m and the width is 16m, we can find the length using the formula 2(length + width) = perimeter. Once you find the length, just multiply it by the width to get the area. Happy painting!
88mm squared
To answer this simply try a few out for yourself. In a 2x1 cm rectangle, the area is 2 cm squared and the perimeter is 6 cm In a 12x10 rectangle, the area is 120 cm squared and the perimeter is 44 cm. In some cases, the perimeter is larger and in others it is smaller. To answer your question, no, the perimeter of a rectangle is NOT always greater than its area.
The perimeter varies, depending on the shape.
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
The perimeter is 18 feet.
== 25x25== 625 Rectangle sides 5 cm each. ==
The dimensions of the rectangle are 3 inches by 14 inches
the old perimeter is 17 * 2 The old perimeter = 38
perimeter = (5+5+12+12)= 34 area = (5*12) = 60 squared
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
Area = 8*24 =192 square feet Perimeter = 24+24+8+8 = 64 feet