It can be infinitely large.
Consider a rectangle of length A cm where A ≥ 7 cm. And let its width be B = 49/A cm.
Then its area is always A*B cm2 = A*49/A cm2 = 49 cm2.
Let A = 10 cm, B = 4.9 cm so perimeter = 29.8 cm
or A = 100 cm, B = 0.49 cm, perimeter = 200.98 cm
or A = 1000 cm, B = 0.049 cm, perimeter = 2000.98 cm
By making the rectangle infinitesimally thin and infinitely long, its perimeter can be increased without limit.
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88mm squared
This question is impossible to answer because the possible length and width of the rectangle could be 15 cm and 4 cm respectively but 15*4 = 60 cm squared and not 60 m squared.
== 25x25== 625 Rectangle sides 5 cm each. ==
The dimensions of the rectangle are 3 inches by 14 inches
perimeter = (5+5+12+12)= 34 area = (5*12) = 60 squared