If the last two digits of a number are divisible by 4, the whole number is divisible by 4. If the sum total of the digits in a number are a multiple of 9, the whole number is a multiple of 9.
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
If they are multiples of 9, the digits add up to a multiple of 9.
In the everyday decimal system of writing numbers . . .-- The largest two digits are 8 and 9.-- Their product is 72.-- 10 less than that is 62 .
11 x 9 = 99 two digits
Yes.A number is divisible by 9 if the sum of the digits is a multiple of 9.18324 = 1 + 8 + 3 + 2 + 4 = 18 (18 is a multiple of 9)A number is divisible by 4 if the last two digits is a multiple of 4.18324 = the last two digits are 24 & it is a multiple of 4.18324 ÷ 9 = 203618324 ÷ 4 = 4581
If the last two digits of a number are divisible by 4, the whole number is divisible by 4. If the sum total of the digits in a number are a multiple of 9, the whole number is a multiple of 9.
I can think of a couple that would work. Like 99. 9+9=18 (multiple of 9), it's odd and has two digits. . The full set is 27 45 63 81 99.
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
The largest digit is 9.
99 is the largest two digit number. If I can use the digits anyway I want, then 9 to the 9th power is larger
If they are multiples of 9, the digits add up to a multiple of 9.
If it's to be a multiple of 9 the its digits must sum to a multiple of 9. Squares under 225 are 196,169,144,121,100... 144 ie 12 squared (and 9 x 16) would seem to be the figure you're looking for.
9*11=99
By 'after 8000' it looks like 'greater than 8000' is what you want.So to get multiple of 4, last 2 digits must be a multiple of 4. {This is because 100 and every multiple of 100 are multiples of 4, so you only have to look at the last two digits}.For multiple of 9, digits must sum up to 9 (or multiple of 9). So 8001 sums up to 9, but it's not multiple of 4. 8010 doesn't work either. So let's look at digits sum to 18. We already have 8, so the last 2 digits sum to 10 would work, and the last 2 digits multiple of 4:19 : 1+9 = 10, but not multiple of 4.28 : 2+8 = 10, and yes it's a multiple of 4.8028 is the answer.