If the last two digits of a number are divisible by 4, the whole number is divisible by 4. If the sum total of the digits in a number are a multiple of 9, the whole number is a multiple of 9.
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
If they are multiples of 9, the digits add up to a multiple of 9.
Is the sum of the digits a multiple of 9?
11 x 9 = 99 two digits
Yes.A number is divisible by 9 if the sum of the digits is a multiple of 9.18324 = 1 + 8 + 3 + 2 + 4 = 18 (18 is a multiple of 9)A number is divisible by 4 if the last two digits is a multiple of 4.18324 = the last two digits are 24 & it is a multiple of 4.18324 ÷ 9 = 203618324 ÷ 4 = 4581
If the last two digits of a number are divisible by 4, the whole number is divisible by 4. If the sum total of the digits in a number are a multiple of 9, the whole number is a multiple of 9.
I can think of a couple that would work. Like 99. 9+9=18 (multiple of 9), it's odd and has two digits. . The full set is 27 45 63 81 99.
The sum of the digits is a multiple of 9
No factor of 9 has three digits. 450 is a three-digit multiple of 150 (and of 9) with a digit sum of 9.
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
The largest digit is 9.
99 is the largest two digit number. If I can use the digits anyway I want, then 9 to the 9th power is larger
If they are multiples of 9, the digits add up to a multiple of 9.
9*11=99
If it's to be a multiple of 9 the its digits must sum to a multiple of 9. Squares under 225 are 196,169,144,121,100... 144 ie 12 squared (and 9 x 16) would seem to be the figure you're looking for.