84x2y2
gcd of 5ab,28xy
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
98
Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.Raise each part to the second power: (28xy)2 = 282x2y2 = 784x2y2.
gcd of 5ab,28xy
4x^(2) + 28xy + 49y^(2) -> (2x)^(2) + 28xy + (7y)^2 Split into brackets ( 2x + 7y)(2x + 7y) If you applyuFOIL you will find toy come to '28xy'. The clue to this problem is to note that '4' ^ '49' are both squared numbers.
2x2 + 28xy + 98y2 = 2(x + 7)2.
The greatest common factor in the two terms is [ 4y ].The factored form of the expression is4y (y + 7x)
To find an expression equivalent to -28xy 35y, we can first simplify by multiplying the coefficients -28 and 35 to get -980. Then, we multiply the variables x and y to get xy^2. Therefore, the expression equivalent to -28xy 35y is -980xy^2.
98
(4x + 7y)(16x2 - 28xy + 49y2)
The LCM of 28 and 42 is 84. Since y2 and x2 are multiples of y and x respectively, they are automatically the LCM. That makes the answer 84x2y2
If you mean 7 times 4y then it is 28y If you mean 7x times 4y then it is 28xy
Do you mean some thing like 4x2 - 28xy + 49y2 ? notice 4x2 = (2x)2 and 49y2 = either (7y)2 or (-7y)2 (1st and last terms must be squares) and the middle term is 2(2x)(-7y) (2 times sq root of 1st times sq root of last) Once the pattern is recognized: (sq root 1st + sqroot 2nd)2 or (sq root 1st - sqroot 2nd)2 depending on if middle term is positive or negative. So, back to my example: 4x2 - 28xy + 49y2 = (2x - 7y)2 because middle is negative. Simpler example factor x2 + 6x + 9. 1st and last are both squares sq root of 9 = 3 3 times 2 = 6 that fits the middle so x2 + 6x + 9 = (x + 3)2