Q: What is the least number with 5 ones?

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2457

7777 + 777*4 + 7*22 + 77 - 7 + 2 = 11111

the 5 as it is 5 thousandths

7 in the ones place

To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.

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2457

If the original number was even, the ones place will be zero; otherwise it will be 5.

7777 + 777*4 + 7*22 + 77 - 7 + 2 = 11111

2005The ones digit is 5.If the ones digit is 5 or 0 then it is divisible by5.NOT a prime.

Factor them both. 1 x 5 = 5 1 x 7 = 7 Discard the common factor (1) and combine the remaining ones 5 x 7 = 35 35 is the lowest (least) number that both 5 and 7 will go into evenly.

the 5 as it is 5 thousandths

When a number is a multiple of 5, the possible values of the ones digit are zero and five.

1 out of 2

7 in the ones place

43 tens and 5 ones.

Only one positive prime number has a 5 in the ones digit. That prime number is 5. All other numbers with a 5 in the ones digit are composite because they will be divisible by 5.

5