2457
7777 + 777*4 + 7*22 + 77 - 7 + 2 = 11111
the 5 as it is 5 thousandths
7 in the ones place
To find if a number is divisible by 5, the digit in the ones place has to be 0 or 5.
2457
If the original number was even, the ones place will be zero; otherwise it will be 5.
0 or 5
2005The ones digit is 5.If the ones digit is 5 or 0 then it is divisible by5.NOT a prime.
7777 + 777*4 + 7*22 + 77 - 7 + 2 = 11111
Factor them both. 1 x 5 = 5 1 x 7 = 7 Discard the common factor (1) and combine the remaining ones 5 x 7 = 35 35 is the lowest (least) number that both 5 and 7 will go into evenly.
the 5 as it is 5 thousandths
When a number is a multiple of 5, the possible values of the ones digit are zero and five.
1 out of 2
7 in the ones place
43 tens and 5 ones.
5