Here is how you do it. If the lenght of the rectangle is L and the Width is W, the perimeter of a rectangle is 2L+2W. To modify this for a square, L=W, so we have 2L+2L where now L is the lenght of a side since all sides have the same length. The formula is 4L. Similarly for the area of a recatangle the formula is LxW, but once again since L=W, we have L2.
No. A rectangle of 1 x 3 has the same perimeter as a rectangle of 2 x 2, but the areas are different.
4x4 square: perimeter - 16 area - 16 6x2 rectangle perimeter - 16 area - 12
Yes. The perimeter is a measure of the combined length of all the sides. If you double the lengths of the sides then naturally this will also necessarilychange the perimeter (it will double the perimeter).
Yes, because you are increasing one of the sides.
The perimeter of a rectangle cannot be determined with the area alone as the lengths could vary. For example, the perimeter of the rectangle could be 12 (1 and 5) or 9 (2 and 2.5). For both cases, the area is still 5cm2, but the length can still change to result in different results.
Yes, the perimeter of a rectangle can be larger than its area. For example, consider a rectangle with dimensions 1 unit by 1 unit, which has a perimeter of 4 units and an area of 1 square unit. As the rectangle's dimensions change, especially when one dimension is much larger than the other, the perimeter can exceed the area even more significantly.
As written, that's confusing. The length and width of a triangle wouldn't have any bearing on the perimeter and area of a rectangle unless they overlap in some drawing that only you are looking at. Let's assume you meant rectangle all along. If the dimensions of a rectangle increased 4 times the perimeter would also increase 4 times. The area would increase 16 times. Try it out. A 2 x 3 rectangle has perimeter 10 and area 6. An 8 x 12 rectangle has perimeter 40 and area 96.
It depends on what side is being decreased All rectangles have perimeter 2l+2w where l is the length and w is the with if the length is decreased by 1 then the rectangle will have perimeter 2(l-1)+2w, similarly if the with is decreased by 1 then it will have perimeter 2l+2(w-1).
Perimeter of a rectangle = 2(length + breadth) if one of it's side is doubled then, the resultant perimeter will be 2(2length + breadth) or 2(length + 2 breadth) as the case may be.
You just have to change the lengths of the sides. For example, if you wanted a perimeter of 20, your rectangle could be... 1x9 with area of 9 2x8 with area of 16 3x7 with area of 21 4x6 with area of 24 5x5 with area of 25 All of these have the same perimeter, but a different area, see?
A perimeter that will not change.
It can be any length you like greater than (or equal to) 4 x √60 ≈ 30.98 A parallelogram is a sheared rectangle; the more the rectangle shears, the longer the originally "vertical" sides (the height of the parallelogram) become. (Shearing does not change the area of the shape.)