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Suppose the length and width are x and y

Perimeter = 2x+2y = 26 so x+y=13 or y=13-x

Area = xy =36 so x*(13-x) = 36

So x2 - 13x + 36 = 0 ie (x-4)*(x-9) = 0

so x = 4 or x = 9 and then y=13-x gives y = 9 or y = 4.

The solution, therefore, is (4,9)

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Q: What is the length and width of a rectangle with a perimeter of 26 inches and an area of 36 square inches?
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