3+3=9 3 and 3
length is 12 width 1
Perimeter maximum 150 so Length + Width = 75; Best fit is 39 ft long and 36 ft wide
Let the length be 4x and the width be x: 2(length)+width = 45 feet of fence used 2(4x)+x = 45 feet 8x+x = 45 9x = 45 x = 5 length = 20 ft and the width = 5 ft Check: 2(20)+5 = 45 ft
For a given perimeter, its a square.
The garden has to be 36-ft by 39-ft. 150-ft of fence will just enclose it, and the area is 1,404 square feet. If the length didn't have to be 3-ft more than the width, then he could make it 37.5-ft square. The same 150-ft of fence would enclose it, but the area would be 1,406.5 square feet ... a full 0.16%, or 2.5 square feet, more.
length is 12 width 1
The length would be 39 feet and the width 36 feet for a perimeter of 150 feet
Perimeter maximum 150 so Length + Width = 75; Best fit is 39 ft long and 36 ft wide
What is the width of Tennessee
If the fence is parallel and extends 10m from each end of the length of the pool, add 20m to the length of the pool to find the length of the fence; find the width of the fence in the same manner. Hence, 50 + 20 = 70m (length of fence); 25 + 20 = 45m (width of fence). 2(L + W) = Perimeter, so 2 x 115m = 230m perimeter
If the width is 5ft and the length is 5ft then the area is 25ft. You just need to multiply the length by the width.
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
A cube cannot have different length, height and width.
Arizona's greatest length is approximately 400 miles from north to south, and its greatest width is around 310 miles from east to west.
A = area, L = length, W = width A = LW L = 2W A = (2W)W = 2W2 2W2 = 50 W = 5 ft
Area is length times width. So in this case it is 10x12 or 120 square feet.
That would depend on the length and width of the acreage.