32
It would be the square root 32 in cm
32 cm
The area is 32 cm2
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
32
It would be the square root 32 in cm
32 cm
The area is 32 cm2
32 cm3
The perimeter of the rectangle is 2•66+2•32=196196/4(sides of a square)=49 cm
A square of perimeter 32cm has 4 sides of length 8cm. Area = Side1*Side2 Area = 8cm*8cm Area=64cm2
That will depend on the length of the other leg but if both legs are 4 cm then by using Pythagoras its hypotenuse is the square root of 32
It is: 128/4 = 32 and 32*32 = 1024 square cm
To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm. To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
Use Pythagoras' theorem: 42+42 = 32 and the square root of this is the length of the hypotenuse
To find the area of a square, you square the length of one of its sides. In this case, if the side of the square is 38 cm, the area would be 38 cm x 38 cm = 1444 square cm. Therefore, the area of the square with a side length of 38 cm is 1444 square cm.