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To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm.
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
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What is the area of a rectangle with a perimeter of 24 and a length of 8?
32
What would be a greater perimeter but a smaller area to a question of 24 and a area of 27?
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
What is the area ad perimeter of a rectangle 27cm wide 32cm long?
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
What is the dimensions of a rectangle for the number 32?
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
What is the length and breadth if area is 60 sq. cm and perimeter is 32 sq. cm of an rectangle?
If the perimeter is 32 sq cm, there is a very serious problem since the perimeter is a linear measure, not an area! Leaving that aside, the length of the rectangle is 10 cm and the breadth is 6 cm.
