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To find the perimeter of a rectangle, you add up the lengths of all its sides. In this case, the rectangle has two sides of 14 cm and two sides of 32 cm. Therefore, the perimeter would be 14 + 14 + 32 + 32 = 92 cm.
To find the area of a rectangle, you multiply the length by the width. In this case, the length is 32 cm and the width is 14 cm. Therefore, the area would be 32 x 14 = 448 square cm.
What else can I help you with?
What is the least perimeter of a rectangle with an area of 32 ft.?
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
What is the area of a rectangle with a perimeter of 24 and a length of 8?
32
What would be a greater perimeter but a smaller area to a question of 24 and a area of 27?
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
What is the area ad perimeter of a rectangle 27cm wide 32cm long?
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
What is the perimeter and area of rectangle 14 cm and 32 cm?
The perimeter of a rectangle is calculated by the formula ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. For a rectangle with dimensions 14 cm and 32 cm, the perimeter is ( P = 2(14 + 32) = 2(46) = 92 ) cm. The area is calculated using the formula ( A = l \times w ), so the area is ( A = 14 \times 32 = 448 ) cm². Therefore, the perimeter is 92 cm and the area is 448 cm².
What is the perimeter of a rectangle with 2Cm length and 14Cm width?
Oh, dude, it's like you're asking me to do math or something. Okay, so to find the perimeter of a rectangle, you just add up all the sides. In this case, you add up 2cm + 2cm + 14cm + 14cm, which equals 32cm. So, the perimeter of your rectangle is 32cm. Easy peasy, lemon squeezy!
What is the least perimeter of a rectangle with an area of 32 ft.?
To find the least perimeter of a rectangle with a fixed area of 32 square feet, we can use the relationship between area and perimeter. For a rectangle, the area ( A = l \times w ) (length times width) and the perimeter ( P = 2(l + w) ). To minimize the perimeter while keeping the area constant, the rectangle should be a square. The side length of a square with an area of 32 ft² is ( \sqrt{32} ), which is approximately 5.66 ft. Thus, the least perimeter is ( 4 \times \sqrt{32} ), which is approximately 22.63 ft.
What is the area of a rectangle with a perimeter of 24 and a length of 8?
32
How do you find the area of a rectangle with a perimeter of 36m?
how do you find the area of a rectangle witha perimeter of 36 in You don't. You need more information For example a 1 x 17 rectangle has a perimeter of 36 and its area is 17. But a 2 x 16 rectangle also has a perimeter of 36 and its area is 32.
What would be a greater perimeter but a smaller area to a question of 24 and a area of 27?
Perimeter = 24 and area = 27 . . . . . rectangle, 3 by 9 Perimeter = 32 and area = 15 . . . . . rectangle, 1 by 15
What it the least perimeter of a rectangle with an area of 32 square feet?
47
What is the perimeter and area of a rectangle with 5 in length and 11 in width?
Perimeter = 32 inches. Area = 55 square inches.
What is the area ad perimeter of a rectangle 27cm wide 32cm long?
Area = 27*32 = 864 square cm Perimeter = 27+27+32+32 = 118 cm
Area of rectangle perimeter 32 units width 6 units?
The area of a rectangle with a perimeter of 32 units and a width of 6 units the area is 80 square units.Improved Answer:-Area = 6*10 = 60 square unitsPerimeter = 6+6+10+10 = 32 units
What is the perimeter and area of rectangle 14 cm and 32 cm?
The perimeter of a rectangle is calculated by the formula ( P = 2(l + w) ), where ( l ) is the length and ( w ) is the width. For a rectangle with dimensions 14 cm and 32 cm, the perimeter is ( P = 2(14 + 32) = 2(46) = 92 ) cm. The area is calculated using the formula ( A = l \times w ), so the area is ( A = 14 \times 32 = 448 ) cm². Therefore, the perimeter is 92 cm and the area is 448 cm².
Two polygons that have the same perimeter but a different area?
For example, a 1x15 rectangle and a 2x14 rectangle. They both have perimeter of 32, but they have areas of 15 and 28, respectively.
What is the dimensions of a rectangle for the number 32?
It is not possible to answer the question because you have not defined what 32 measures: is it the area of the rectangle, its perimeter, its diagonal or some other property?
