If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.
To construct quadrilateral ABCD with specified lengths for sides AB, BC, CD, and diagonals AC and BD, start by drawing triangle ABC with the given lengths for sides AB and BC. Use the length of AC to find point C, ensuring that it connects to the endpoint of BC. From point A, draw line segment AD such that it matches the length of AD, then connect point C to point D to complete the quadrilateral, ensuring that the length CD is also as specified. Make sure to use a compass and straightedge for accurate measurements.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
To find the possible length for side AB in triangle ABC with sides BC = 12 and AC = 21, we can use the triangle inequality theorem. The sum of the lengths of any two sides must be greater than the length of the third side. Therefore, we can write the inequalities: AB + BC > AC → AB + 12 > 21 → AB > 9 AB + AC > BC → AB + 21 > 12 → AB > -9 (which is always true) BC + AC > AB → 12 + 21 > AB → 33 > AB or AB < 33 Combining these, we get the inequality: 9 < AB < 33.
you use Pythagoras theorem. Square of the Hypotenuse = square of the other 2 sides i.e ac squared = ab squared + bc square = 22 Squared + 32 Squared = 484 + 1024 = 1508 so ac = square root of 1508 = 38.83 cm(2 d.p)
If the quadrilateral is a square then all of its sides are the same length. ac is not one of the sides but is a diagonal which forms the hypotenuse of a right angle triangle with sides ab and bc. According to Pythagoras the sum of the square of the hypotenuse is equal to the sum of the squares of the other two sides. As side ab measures 10 then 10 squared = 100. Side bc has the same measurements. The square of side ac must equal 200 (100 + 100) so the length of side ac must equal the square root of 200 (100 + 100) which is 14.14 (to 2 decimal places).
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If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)
If line BE is the bisector of segment AC, it means that it divides AC into two equal parts. Given that AB is 7 units, it implies that the length of AC is twice the length of AB. Therefore, AC is 2 × 7 = 14 units.
To construct quadrilateral ABCD with specified lengths for sides AB, BC, CD, and diagonals AC and BD, start by drawing triangle ABC with the given lengths for sides AB and BC. Use the length of AC to find point C, ensuring that it connects to the endpoint of BC. From point A, draw line segment AD such that it matches the length of AD, then connect point C to point D to complete the quadrilateral, ensuring that the length CD is also as specified. Make sure to use a compass and straightedge for accurate measurements.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
you use Pythagoras theorem. Square of the Hypotenuse = square of the other 2 sides i.e ac squared = ab squared + bc square = 22 Squared + 32 Squared = 484 + 1024 = 1508 so ac = square root of 1508 = 38.83 cm(2 d.p)
To find the length of AC, use the Pythagorean theorem. AC equals the square root of (AB squared + BC squared), which is the square root of (9 squared + 12 squared), giving AC = square root of (81 + 144) = square root of 225 = 15 centimeters.
sqrt(ab^2 + bc^2)
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To find the length of segment AB, we can use the segment addition postulate, which states that the total length of a segment is equal to the sum of the lengths of its parts. Therefore, AB + BC = AC. Given that AC = 78 mm and BC = 29 mm, we can substitute these values into the equation to find AB: AB + 29 = 78. Solving for AB, we get AB = 78 - 29 = 49 mm.
If line BE is the bisector of segment AC, it means that BE divides AC into two equal segments. Therefore, if AB is 7, then AC must be twice that length, making AC equal to 14.