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30 radical 2
if it is a cube each side is 9 inches ( cube root of 729); 9 x 9 x 9 - 729
Each of them is 14.14 inches long. (rounded)
The surface of the cube is 6 times this length squared - 6L2.
To find the length of each diagonal of a square, divide the sum of the diagonal lengths by 2. Since a square has two diagonals of equal length, this division will give you the length of each diagonal.
30 radical 2
if it is a cube each side is 9 inches ( cube root of 729); 9 x 9 x 9 - 729
The volume of a cube is the cube of the length of one edge. (9 inches)3 = 729 cubic inches.
Each of them is 14.14 inches long. (rounded)
The surface of the cube is 6 times this length squared - 6L2.
Each edge measures five inches.
The distance between two tetrahedral voids is 0.866*edge length of the cube.As tetrahedral voids are present at 1/4th of the distance from each corner on a body diagonal of a cube.On each body diagonal there are two tetrahedral voids so making a total of 8 tetrahedral voids in an FCC cube. the distance between two tetrahedral voids is half of the body diagonal of a cube and the body diagonal of a cube is1.732 times of the edge length of the cube
20 inches each side.
To find the length of each diagonal of a square, divide the sum of the diagonal lengths by 2. Since a square has two diagonals of equal length, this division will give you the length of each diagonal.
Each side is sqrt 72 ie 8.49 in
If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s
Surface area of a cube A = 6*L^2 where L is the length of each side. L = sqrt(A/6) = 8.