32.6 (rounded to 1 dp.)
Method;
Area = length x width
Rearranging ...
Length = Area / width
Length = 228/7 = 32.6
The perimeter is 2 x (101 + 228) = 658 feet
The dimensions of the room would be 12 feet wide by 19 feet long. 12 x 19 = 228.This can solved by first understanding the question in terms of 2 algebraic expressions:a. first that the length and width of the room multiplied together is 228 ft^2, or written algebraically as l * w = 228.b. secondly that the length is 7 feet longer than the width, or written algebraically as l-7 = w.Net result is that there are 2 different equations with 2 different unknowns. Using integers this can now either be solved through trial and error or resolved algebraically.a. l*w = 228b. l-w = 7
if perimeter is 228 inches then each side is 228/6 = 38 inches since haxagon has 6 equal sides
75 percent off of 228 = 5775% off of 228= 75% discount applied to 228= 228 - (75% * 228)= 228 - (0.75 * 228)= 228 - 171= 57
19
The width is 228/12 = 19 feet
Let the width be (x-7) and the length be x: width*length = area (x-7)*x = 228 sq ft x2-7x-228 = 0 Solving the above quadratic equation works out as: x = -12 or x = 19 it must be the latter because dimensions can't be negative. Therefore: length = 19 feet and width = 12 feet
228 feet is the perimeter.
width + length x 2 or w + l x 2 or w + L2
228 inches, what you do is add, 97+97+17+17
Multiply width by length to get the area. The answer would be 228 square feet.
Area is length multiply by breath.So room is 228 square feet in area.
The perimeter is 2 x (101 + 228) = 658 feet
To get the area you multiply the length and the width. Doing the math gives an answer of 228 square feet. Divide by 9 gives you 25.33 square yards.
The dimensions of the room would be 12 feet wide by 19 feet long. 12 x 19 = 228.This can solved by first understanding the question in terms of 2 algebraic expressions:a. first that the length and width of the room multiplied together is 228 ft^2, or written algebraically as l * w = 228.b. secondly that the length is 7 feet longer than the width, or written algebraically as l-7 = w.Net result is that there are 2 different equations with 2 different unknowns. Using integers this can now either be solved through trial and error or resolved algebraically.a. l*w = 228b. l-w = 7
If the numbers provided are inches, then the room contains 228 Square feet.
228 meters (4 sides x 57 = 228)