Let the width be (x-7) and the length be x:
width*length = area
(x-7)*x = 228 sq ft
x2-7x-228 = 0
Solving the above quadratic equation works out as:
x = -12 or x = 19 it must be the latter because dimensions can't be negative.
Therefore: length = 19 feet and width = 12 feet
98 square feet
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Surface area = length*width in square units
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
For a rectangle or square, Area = Length * Width So Length = Area / Width.
Multiply the length and width to find the area of both a rectangle and square.
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
width=16 and length=20
To find the area of a rectangle, you simply multiply its length by its width. In this case, the length is 21m and the width is 17m. Therefore, the area of the rectangle would be 21m x 17m = 357 square meters.
Area= Length multiplied by Width
Area= Length multiplied by Width
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
Area is length times width: 140 square feet.
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
7
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.