Let the width be (x-7) and the length be x:
width*length = area
(x-7)*x = 228 sq ft
x2-7x-228 = 0
Solving the above quadratic equation works out as:
x = -12 or x = 19 it must be the latter because dimensions can't be negative.
Therefore: length = 19 feet and width = 12 feet
98 square feet
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
Surface area = length*width in square units
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
For a rectangle or square, Area = Length * Width So Length = Area / Width.
Multiply the length and width to find the area of both a rectangle and square.
-- Multiply the rectangle's length by itself. ('square' the length) -- Multiply the rectangle's width by itself. ('square' the width) -- Add the two results. -- Find the square root of the sum. It is the length of the diagonal.
width=16 and length=20
Area= Length multiplied by Width
Area= Length multiplied by Width
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
Area is length times width: 140 square feet.
7
To find the area of a rectangle, multiply the length times the width. The result will be in square inches.
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
It is not possible.