The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
This is your lucky day ! Watch now, as the Great and Powerful WA Contributorsolves your problem and answers your question without ever seeing the drawingthat's supposed to go along with it, and with no idea what 'BC' and 'ab' are . . .-- A whole circle has a central angle of 360 degrees.-- A whole circle with a radius of 10 has a circumference of [ (2 pi) x (radius) ] = 20 pi .-- A slice of cake with a central angle of 120 degrees is 1/3 of a circle.-- The arc at the fat end of the slice is 1/3 of the full circle's circumference = 20 pi/3 = 20.944 (rounded)-- Just in case 'BC' is the long arc, then its length is the other 2/3 of the whole circle= 2 x 20 pi/3 = 41.888 (rounded)Pay no attention to that old man behind the curtain.
Draw a horizontal line AB equal to one of the side lengths. From A draw an arc of a circle of radius one of the remaining lengths. From B draw an arc of a circle of radius the third length. Where the arcs intersect is point C. Join AC and BC. Voila!
10 BC was in the first century BC.
It would be a straight line of length bc
26.17
The length of the arc of ABC is 22pi. You can get this answer by completing this equation 330/360*24pi, which will give you 22pi.
This is your lucky day ! Watch now, as the Great and Powerful WA Contributorsolves your problem and answers your question without ever seeing the drawingthat's supposed to go along with it, and with no idea what 'BC' and 'ab' are . . .-- A whole circle has a central angle of 360 degrees.-- A whole circle with a radius of 10 has a circumference of [ (2 pi) x (radius) ] = 20 pi .-- A slice of cake with a central angle of 120 degrees is 1/3 of a circle.-- The arc at the fat end of the slice is 1/3 of the full circle's circumference = 20 pi/3 = 20.944 (rounded)-- Just in case 'BC' is the long arc, then its length is the other 2/3 of the whole circle= 2 x 20 pi/3 = 41.888 (rounded)Pay no attention to that old man behind the curtain.
the answer is 98
100 degrees :)
22
JNo empire ended in 120 BC. Greco-Bactria ended in 125 BC, but that was a kingdom. The Maurya Empire ended in 185 BC
Hipparchus of Nicaea, (190 BC to 120 BC).
Hipparchus of Nicaea (190 BC to 120 BC).
Draw a horizontal line AB equal to one of the side lengths. From A draw an arc of a circle of radius one of the remaining lengths. From B draw an arc of a circle of radius the third length. Where the arcs intersect is point C. Join AC and BC. Voila!
Use Pythagoras' theorem to find the 3rd side
Hipparchus of Nicaea, 190 BC to 120 BC.