130 What! How about one tenth of its perimeter?
The formula for determining the area of a decagon is A = 2.5dt where t is the length of one edge and d is the distance between two parallel sides
10*length of a side.
5xy
It is: 58/10 = 5.8 units of length
130 What! How about one tenth of its perimeter?
find the perimeter of a decagon if all off the sides equal 4mi.
A decagon has 10 sides. If it is a regular decagon, all of the sides are the same length. Each side would be 0.8 yards or 2.4 feet in length.
12cm a decagon is 10 sides 120/10=12
The formula for determining the area of a decagon is A = 2.5dt where t is the length of one edge and d is the distance between two parallel sides
A decagon has 10 sides, therefore, with side length 13.5 centimetres, the perimeter would be 13.5 x 10 = 135 centimetres.
10*length of a side.
8 yds * * * * * That is simply nonsense. In a regular decagon, each of the 10 sides is of the same length. So the length of each side is 22/10 = 2.2 feet.
5xy
It is: 58/10 = 5.8 units of length
A decagon has 10 equal sides, so if the perimeter is 120 cm each side must be 12 cm
Any polygon is regular if its sides are all the same length, or irregular if they're not. If all 10 sides of your decagon are the same length, then you have a regular decagon. If they're not, then you have an irregular one.