Wiki User
∙ 12y agoAha! A question for Arturo Pythagoras!
Slope = sqrt(100 + 225), = 18 ft and a third of an inch
Wiki User
∙ 12y agoa2 +b2=c2102 + 152 =c2c=18.03 feet
Neglecting air resistance, the components of acceleration of an object that's dropped, tossed, pitched, flung, lobbed, heaved, launched, or shot are constant. The horizontal component is zero. The vertical component is 9.8 meters per second2, directed downward. These are both constant throughout the object's trajectory.
"Up and down" is vertical. Side to side (or across) is horizontal. An easy way to remember this is "horizontal" runs like the horizon. The vertical measurment is usually referred to as the height. The length would be the horizontal measurement.
A trapezoid has one height: vertical measurement from top to bottom, and two bases: horizontal measurement on top and horizontal measurement on bottom. To find the area, you add the two bases together, multiply that by the height, and then divide by 2.
Area = 1/2 b h b : base h : height The height is vertical side of the right angle; the base is the horizontal side of the right angle
18 feet
a2 +b2=c2102 + 152 =c2c=18.03 feet
The length of the downward sloping side of the ramp would be 18 feet approximately this is pythagarus theorem of the sum of squares. the answer should in fact be the number corresponding to the square root of (10*10+15*15).
Pythagoras rules! The slope will be the square root of (100 + 225) ft ie 18 ft and a third of an inch.
The answer depends on the direction (upward, horizontal, or downward) in which the ball leaves his foot.
The opposite of a height is a depth. The opposite direction measurement of height (vertical) is width (horizontal).
The opposite of a height is a depth. The opposite direction measurement of height (vertical) is width (horizontal).
The height of collimation is the height of the line of sight. It is the vertical distance of the horizontal plane through a telescope.
Neglecting air resistance, the components of acceleration of an object that's dropped, tossed, pitched, flung, lobbed, heaved, launched, or shot are constant. The horizontal component is zero. The vertical component is 9.8 meters per second2, directed downward. These are both constant throughout the object's trajectory.
The horizontal component of a projectile's velocity doesn't change, until the projectile hits somethingor falls to the ground.The vertical component of a projectile's velocity becomes [9.8 meters per second downward] greatereach second. At the maximum height of its trajectory, the projectile's velocity is zero. That's the pointwhere the velocity transitions from upward to downward.
The angle of projection affects the maximum height by determining the vertical and horizontal components of the initial velocity. At 90 degrees (vertical), all the initial velocity is vertical which results in maximum height. As the angle decreases from 90 degrees, the vertical component decreases, leading to a lower maximum height.
"Up and down" is vertical. Side to side (or across) is horizontal. An easy way to remember this is "horizontal" runs like the horizon. The vertical measurment is usually referred to as the height. The length would be the horizontal measurement.