If: x-2y = 8 and xy = 24
Then: x = 8+2y and y(8+2y) = 24 => 2y^2+8y-24 = 0
Solving the above quadratic equation: y = 2 or y = -6
Points of intersection of the line with the curve: (-4, -6) and (12, 2)
Length of line: square root [(-4-12)^2 plus (-6-2)^2] = square root of 320 which is about 18 units rounded to the nearest integer
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
If: y = x^2 +2x -7 and y = 17 -3x Then: x^2 +2x -7 = 17 -3x => x^2 +5x -24 = 0 Solving the equation: x = 3 or x = 8 Points of intersection: (3, 8) and ( -8, 41) Length of line: square root of 1210 which is about 34.785 to three decimal places
If: y = 17-3x and y = x^2+2x-7 Then: x^2+2x-7 = 17-3x => x^2+5x-24 = 0 Solving the quadratic equation: x = -8 and x = 3 Points of intersection with the parabola: (-8, 41) and (3, 8) Length of line: square root of [(-8-3)^2+(41-8)^2] = 34.785 to 3 d.p.
If: y = x^2 +4 and 5x+10-y = 0 or y = 5x+10 Then: x^2 +4 = 5x +10 or x^2-5x-6 = 0 Solving the above quadratic equation: x = -1 or x = 6 By substitution end points of the line are at: (6, 40) and (-1, 5) Length of line is the square root of: (-1-6)^2 plus (5-40)^2 = 36 rounded
If: y -x = 7 Then: y = 7+x If: y = 8/x Then: xy = 8 Therefore it follows that: x(7+x) = 8 So: 7x+x^2 = 8 => 7x^2 -8 = 0 Using the quadratic equation formula: x = -8 or x = 1 By substitution the line intercepts the curve at (-8, -1) and (1, 8)
The line x-y = 2 intersects with the curve x^2 -4y^2 = 5 at (2.5, 1/3) and (3, 1) and by using the distance formula its length is 5/6
If you mean: y = 17-3x and y = x^2+2x-7 then the length of the line works out as 11 times square root of 10 or about 34.785 to three decimal places.
If: y = 4x2-2x-1 and y = -2x2+3x+5 Then the length of the line works out as: 65/18 or 3.6111 ... recurring decimal 1
If: y = x^2 +2x -7 and y = 17 -3x Then: x^2 +2x -7 = 17 -3x => x^2 +5x -24 = 0 Solving the equation: x = 3 or x = 8 Points of intersection: (3, 8) and ( -8, 41) Length of line: square root of 1210 which is about 34.785 to three decimal places
First find the points of intersection of the two equations: 17 - 3x = x2 + 2x - 7 or x2 + 5x - 24 = 0 This has the solutions x = 3 and x = -8 So the coordinates of the two points of intersection are (3,8) and (-8,41). Then, by Pythagoras, the length is sqrt[(3+8)2 + (8-41)2] = sqrt(121 + 1089) = sqrt(1210) = 11 sqrt(10) or 34.785 units (approx).
If: y = 17-3x and y = x^2+2x-7 Then: x^2+2x-7 = 17-3x => x^2+5x-24 = 0 Solving the quadratic equation: x = -8 and x = 3 Points of intersection with the parabola: (-8, 41) and (3, 8) Length of line: square root of [(-8-3)^2+(41-8)^2] = 34.785 to 3 d.p.
The Brahmaputra River spans through Bangladesh, China and India.Its source is the Chemayungdung Glacier and and the length of it runs for 1,802 miles.
If: y = x^2 +4 and 5x+10-y = 0 or y = 5x+10 Then: x^2 +4 = 5x +10 or x^2-5x-6 = 0 Solving the above quadratic equation: x = -1 or x = 6 By substitution end points of the line are at: (6, 40) and (-1, 5) Length of line is the square root of: (-1-6)^2 plus (5-40)^2 = 36 rounded
75 feet long refers to a measurement of length where an object or distance spans 75 feet.
If: y -x = 7 Then: y = 7+x If: y = 8/x Then: xy = 8 Therefore it follows that: x(7+x) = 8 So: 7x+x^2 = 8 => 7x^2 -8 = 0 Using the quadratic equation formula: x = -8 or x = 1 By substitution the line intercepts the curve at (-8, -1) and (1, 8)
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
Points: (2, 3) and (5, 7) Length of line: 5 Slope: 4/3 Perpendicular slope: -3/4 Midpoint: (3.5, 5) Bisector equation: 4y = -3x+30.5 or as 3x+4y-30.5 = 0