There can be no line because there is no equation.
Limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a more helpful answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y) 2.
5
x - y - 2 = 0-y = -x + 2y = x - 2The graph is a straight line. The slope of the line is [2].The line intersects the x-axis at [x=2], and the y-axis at [y=-2].
A vertical line that passes through -2 on the x-axis.
I understand this to mean x = 2. This is the vertical line passing through the (2, 0) or, alternatively, the vertical line passing through the point where x = 2 on the x-axis.
Any line of the form x = some_number. eg all the lines: x = -2 x = 0 x = 1.2 are perpendicular to y = -2.
Imagine the set up: line 1 X line 2 X X line 3 X X X line 4 X X X X line 5 (empty) Move the pin from line 1 to the centre of line 5. line 1 (empty) line 2 X X line 3 X X X line 4 X X X X line 5 X Now move the 2 outer pins on line 4 to the outer position on line 2 line 1 (empty) line 2 X X X X line 3 X X X line 4 X X line 5 X And there you go. Except the spacings I used weren't saved. I hope you get the idea though!
5
x - y - 2 = 0-y = -x + 2y = x - 2The graph is a straight line. The slope of the line is [2].The line intersects the x-axis at [x=2], and the y-axis at [y=-2].
A vertical line that passes through -2 on the x-axis.
I understand this to mean x = 2. This is the vertical line passing through the (2, 0) or, alternatively, the vertical line passing through the point where x = 2 on the x-axis.
4
Any line of the form x = some_number. eg all the lines: x = -2 x = 0 x = 1.2 are perpendicular to y = -2.
x-3y+2 = 4 -3y = -x+4-2 -3y = -x+2 y = 1/3x-2/3 Slope or gradient of the perpendicular line is -3 Use y-y1 = -3(x-x1) to find the perpendicular equation
Y = (X+4) / 2 is a straight line parallel to Y = 0.5 * X
On your graph, draw a vertical line through the point on the x-axis where [ x = -2 ]." X is less than or equal to -2 " is every point on that line and everything to the left of it.
I don't see an equals sign. Let's assume you mean y = x - 2. The gradient (coefficient) of x is +1. So for a line perpendicular this this, the gradient/slope need to be -1. So the equation of the line perpendicular to this is y = -x +c To find c, substitute x=-2 and y=4. This give c=2 So the line you want is y = -x +2
X intercept of -1 means that the line passes through (-1,0) y intercept of 2 means that the line passes though (0,2) The equation of this line is (y - y1) = [(y2 - y1)/(x2 - x1)] x (x - x1), that is y - 0 = [(2 - 0)/(0 + 1)] x (x +1), that is y = (2) x (x +1) or y = 2x + 2 Verification: In the equation y = 2x + 2 1) substitute -1 for x and y evaluates to 0; 2) substitute 0 for x in the equation and you get y as 2 which means this line passes through (-1,0) and (0,2)