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How can i graph c -4 2 and slope 3 2?
You can graph X -4 2 and slope 3 2 by first finding the values of X and Y and then using those values to sketch your graph.
How do you graph fx-x-1 3 gx-x-2 and hx -3x-1?
graph G(x)=[x]-1
How many times does the graph of y equals x2-4x plus 4 intersect the x-axis?
y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.
How would you graph the solution to x 4 -2?
6
How do you graph a parabola on a TI 84 calculator?
hit Y= hit X,T,O,n hit X2 hit graph so you have put y = x2 into your equations window then graphed it you can change the graph around: to put graph up x amount, plug in a c value. ex: (x^2)+2. that will make the graph shift 2. if you want it the shift sideways. add the translation amount to every x. ex: 4x^2+3x+6 would be 4(x+2)^2+3(x+2)+6 to shift the parabola 2 to the side. a b value ( B(X) ) shifts the graph
How can you translate the graph of y equals x to obtain the graph of y equals x-4 plus 2?
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
Where does the graph of x2 - x - 2 y cross the x-axis?
y = x^2 - x - 2 This is the graph of a parabola. We need to find the x-intercepts. Set 0 for y, and solve for x: 0 = x^2 - x - 2 0 = (x + 1)(x - 2) x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Thus, x-intercepts are -1 and 2. The graph of y = x^2 - x - 2 crosses the x-axis at x = -1 and x = 2.
Graph x equals y plus 2?
x=y+2 y=x-2 The y value at the x axis (x=0) will be -2, so graph (0, -2). Let's calculate a few more points by varying x and calculating y: if x=2, y=2-2=0 (2, 0) similarly: (1, -1) (5, 3) Graph those points, then draw a line connecting them all. That's the graph of x=y+2.
How can i graph c -4 2 and slope 3 2?
You can graph X -4 2 and slope 3 2 by first finding the values of X and Y and then using those values to sketch your graph.
How do you graph fx-x-1 3 gx-x-2 and hx -3x-1?
graph G(x)=[x]-1
If f(x) is the graph of f(x) translated down 2 units?
f(x) cannnot be a graph of itself translated down by anything other than 0 units.
How many times does the graph of y equals x2-4x plus 4 intersect the x-axis?
y=x2-4x+4 y = (x-2)(x-2) x=2 the graph only crosses the x-axis at positive 2. this is the minimum of the graph and the only point that is crosses the x-axis.
What is the correct graph ffor x3 and x-2?
what is the anwer for x=3 and x=2
Can there be a graph of a function be a vertical?
Yes. The graph of [ x = 2 ] is a vertical line.
What does a line graph look like if x-2 and x3?
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
How can the graph of a fourth degree polynomial have its only x intercepts 0 1 and 2?
Easy. Same thing as the graph of f(x) = x^2 + 1 which have NO intercept.
What describes how to translate the graph y x to obtain the graph of y x plus 1 plus 1?
You move the graph upwards by 2 units.
