5a - 10 = 4a + 8 is a linear equation in one variable.
It is an equation and the value of a is 7
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
x-2y+bz=3 ax+2z=2 5x+2y=1 find values of a and b for which the system of linear equation has infinitely many solutions
4a - 2.1 = 9a + 5.4 4a - 9a = 5.4 +2.1 -5a = 7.5 -a = 1.5 a = -1.5
5a - 10 = 4a + 8 is a linear equation in one variable.
If 4a+24=72 then you start out by subtracting 24 from both sides because what you do to one side of the equation you must do to the other. That means that 4a+24-24=72-24. So 4a=48. Now you divide both sides by 4 and you get a=12.
It is an equation and the value of a is 7
Solve the following equation for A : 2A/3 = 8 + 4A
4a - 5b = 74a +5b = 17From the first equation:4a = 7 + 5bsubstitute this value in the second equation:7 + 5b + 5b = 177 + 10b = 1710b = 10b = 1Now,solve for a :4a - 5(1) = 74a = 7 + 54a = 12a = 3
x-2y+bz=3 ax+2z=2 5x+2y=1 find values of a and b for which the system of linear equation has infinitely many solutions
4a - 2.1 = 9a + 5.4 4a - 9a = 5.4 +2.1 -5a = 7.5 -a = 1.5 a = -1.5
Add the equations: 4a + 4a - 5b + 5b = 7 + 17 ie 8a = 24 a = 3, so b = 1
8a+4a=144 12a=144 12a/12=144/12 A=144
4a + 6 - 4a = -10 Combining like terms: 6 = -10 or 4 = 0 which is FALSE. So the solution set is empty.
You would need to know what a is equal to in order to calculate this equation.
It is an equation in the single unknown variable, a. a = -4