Assuming you are asking about the natural logarithms (base e):
log (-1) = i x pi
therefore
log (log -1) = log (i x pi) = log i + log pi = (pi/2)i + log pi which is approximately 1.14472989 + 1.57079633 i
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Yes. The logarithm of 1 is zero; the logarithm of any number less than one is negative. For example, in base 10, log(0.1) = -1, log(0.01) = -2, log(0.001) = -3, etc.
The logarithm of [ 1 x 109 ] is 9.00000
If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.
The natural logarithm (ln) is used when you have log base e
If a^x = n, where a is a positive real number other than 1 and x is a rational number then logarithm is defined as, logarithm of n to the base a is x. Then is written as log n base a = x.