I suppose you mean log21 - the logarithm of 1, to the base 2. The logarithm of 1 (in any base) is zero, since x0 = 1 for any "x".
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the value of log (log4(log4x)))=1 then x=
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
log (21.4 ) = 1.4 log(2) = 1.4 (0.30103) = 0.42144 (rounded)
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
inverse log of 2= 1/(log{10}2)= 1/(log2)=1/0.3010299=3.3219. hence answer is 3.3219