You obtain the absolute minimum of the function when x=0. (0^4)-2 =0-2=-2. So, the lower bound of the function is -2.
The lower bound of 5.56 to 2 decimal places is 5.555. This is because the lower bound represents the smallest value that rounds up to 5.56 when rounded to two decimal places. Therefore, any value from 5.555 up to but not including 5.565 will round to 5.56.
sqrt(x4) = x4/2 = x2
24
N = x4 x8 = x4+4 = (x4)2 = N2
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
j
0.039
4.46 is a fixed number: it has no upper nor lower bound. To 2 dp it is 4.46
sqrt(x4) = x4/2 = x2
264
the answer is 2
24
x4
N = x4 x8 = x4+4 = (x4)2 = N2
(x - 2)(x + 2)(x^2 + 4)
x4 - 4x3 - 12x2 -32x + 64 (x - 4)(x + 2)(x + 2)(x - 4)
(x^2 - 2x + 2)(x^2 + 2x + 2)