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How do you factor x4-9?

(x^2 - 3)(x^2 + 3)


What is the factor of x4-13x2 plus 36?

(x - 2)(x + 2)(x - 3)(x + 3)


How do you factor this x4-x2-12?

I assume the x4 is x to the 4th power, and x2 is x², or x squared. The two factors would be: (x + 2)(x - 2)(x² + 3) There are 4 solutions for x: x = 2 x = -2 x = √-3 x = -√-3


How do you factor x to the 8th-9?

(x4 - 3)(x4 + 3)


Antiderivative of x cubed divided by 3?

f'(x) = x^(3) / 3 Hence f(x) = 3x^(2) / 3 +C f(x) = x^(2) + C ' The '3' cancels out. The 'C' is a constant that comes with antoderivation.


What is the Greatest Common Factor of x4 and x3?

Greatest common factor of x4 and x3 is x3.


How do you factor x4 plus 4x3-7x-34x-24?

(x - 3)(x + 1)(x + 2)(x + 4)


What is the square root of x to the fourth?

sqrt(x4) = x4/2 = x2


How do you factor x4-16?

(x - 2)(x + 2)(x^2 + 4)


What is an example of factor by grouping?

3x3 + 6x2 + x + 2 3x2 (x + 2) + (x + 2) (x + 2) (3x2 + 1) OR 3x3 + x + 6x2 + 2x (3x2 + 1) + 2 (3x2 + 1) (3x2 + 1) (x + 2) Check: (x + 2) (3x2 + 1) = 3x3 + x + 6x2 + 2 = 3x3 + 6x2 + x + 2 x3 - 3x2 - 4x + 12 x2 (x - 3) - 4 (x - 3) (x - 3) (x2 - 4) (x - 3) (x + 2) (x - 2) Check: (x - 3) (x + 2) (x - 2) = (x - 3) (x2 - 4) = x3 - 4x - 3x2 + 12= x3 - 3x2 - 4x + 12=== === x5 - x4 + 8x3 - 8x2 + 16x - 16 x4 (x - 1) + 8x2 (x - 1) + 16 (x - 1) (x - 1) (x4 + 8x2 + 16) (x - 1) (x2 + 4)(x2 + 4) (x - 1) (x2 + 4)2 Real Solution (x - 1) (x + 2i) (x - 2i) (x + 2i) (x - 2i) (x - 1) (x + 2i)2 (x - 2i)2 Check: (x - 1) (x + 2i)2 (x - 2i)2 = (x - 1) (x + 2i) (x - 2i) (x + 2i) (x - 2i) = (x - 1) (x2 + 2xi - 2xi - 4i2) (x2 + 2xi - 2xi - 4i2) = (x - 1) (x2 - 4(-1)) (x2 - 4(-1)) = (x - 1) (x2 + 4) (x2 + 4) = (x - 1) (x4 + 4x2 + 4x2 +16) = (x - 1) (x4 + 8x2 + 16) = x5 + 8x3 +16x - x4 - 8x2 - 16 = x5 - x4 + 8x3 - 8x2 + 16x - 16


Which expression is equivalent to x8-256?

264


How many cubes does 2 by 3 by 4 hold?

2 cubes wide x 3 cubes long x 4 cubes high. 2 X 3 X4 6 X 4 24 cubes