-9,999,999,999 or, if dealing only with positive integers, 1,000,000,001
11 - if you mean lowest 2 digit odd number, as 10 is even.
The smallest two-digit odd number is 11. It is the first odd number that falls within the range of two-digit numbers, which start from 10.
1000/10 = 100
To find the number of five-digit odd numbers where the leftmost digit cannot be zero, we consider the structure of a five-digit number: ABCDE. The leftmost digit (A) can be any digit from 1 to 9 (9 choices). The last digit (E) must be odd, which gives us 5 choices (1, 3, 5, 7, or 9). The middle three digits (B, C, D) can each be any digit from 0 to 9 (10 choices each). Thus, the total number of such five-digit odd numbers is (9 \times 10 \times 10 \times 10 \times 5 = 45000).
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?
11 - if you mean lowest 2 digit odd number, as 10 is even.
10 is the lowest two digit number.
The smallest two-digit odd number is 11. It is the first odd number that falls within the range of two-digit numbers, which start from 10.
10
10
10
1,000,009
1000/10 = 100
The smallest 2 digit whole number is 10 The smallest 2 digit odd whole number is 11
10. Any number can be squared or cubed.
To find the number of five-digit odd numbers where the leftmost digit cannot be zero, we consider the structure of a five-digit number: ABCDE. The leftmost digit (A) can be any digit from 1 to 9 (9 choices). The last digit (E) must be odd, which gives us 5 choices (1, 3, 5, 7, or 9). The middle three digits (B, C, D) can each be any digit from 0 to 9 (10 choices each). Thus, the total number of such five-digit odd numbers is (9 \times 10 \times 10 \times 10 \times 5 = 45000).
There cannot be a proper three digit number between 10 and 20. It must be a two digit number. If you consider a 2-digit number between 10 and 20, then its tens digit MUST be 1 and so MUST be odd. So most of this question is either wrong or irrelevant. Are you sure you have not cut and pasted bits from two questions?