HCF(5, 8) + 1 = 40 + 1 = 41
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
forty-one
It is LCM(5, 8) + 1 = 41.
41
0, 1, 2, or 3.
234568
5
41
41
The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3
forty-one
12
It is LCM(5, 8) + 1 = 41.
41
6172839
0, 1, 2, or 3.
When a positive integer is divided by 3, the possible remainders are 0, 1, and 2. This is because any integer can be expressed in the form of (3k), (3k + 1), or (3k + 2) for some integer (k). Thus, the remainder will always fall within this set of values.