That really depends upon how you define the question; as an algebra question, the answer would be -999. In an enumerated list, you might start with 001. In terms of counting numbers, you don't get to three digits until 100. So you have at least three possible answers.
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Absolutely ! There are many solutions - the lowest is... 1999-999=1000 *Side note* Actually, the solution when looking for the lowest value of the term that still gives you a four-digit differance, has to be found in the answer of 1100 - 100 = 1000, since 100 is the - using your word- "lowest" value of a three digit-number, as well as 1000 being the "lowest" four-digit number.
The lowest two-digit prime number is 11.11.
100 is the lowest three diget number divisible by 4.
Its Impossible. I say this because anything that is three digits divided by a one digit number that equals 8 is not possible. For example the higher 1 digit number that you can multiply by eight is nine so I did 8x9 and got 72 which is not a three digit number. The lowest three digit number that 8 goes into is 104 which is 13x8 and 13 is not a one digit number. Therefore the problem is impossible. :)