2g/cm3
The idea is to divide the mass by the volume.
density = mass / volume density = 0.250 kg / (0.05 m)3 density = 0.250 kg / 0.000125 m3 density = 2000 kg/m3 (For comparison, pure water's density is about 1000 kg/m3)
Marshmallows vary in density. They are not a pure substance. As they contain air bubbles their density can be altered merely by squeezing them as can their volume but their mass would be the same even if smashed into pieces. The marshmallow's physical dimensions would change.
Pure water at standard temperature and pressure has density of 1 kg/L.1.2 Liter = 1.2 kg
Approximately 6g. The density of pure water at 20 degrees centigrade and standard atmospheric pressure is 1 g/ml. The answer is approximate since the water may not be chemically pure and you do not give a temperature or pressure.
Density is calculated as mass divided by volume. In this case, the mass of the silicon sample is 820g and the volume of the container is 350 cm^3. Therefore, the density of the silicon sample in the container is 820g / 350 cm^3 = 2.34 g/cm^3.
Density is calculated as mass divided by volume. In this case, the mass is 820g and the volume is 350 cm3. Density = 820g / 350 cm3 ≈ 2.34 g/cm3.
The density of the sample is calculated by dividing the mass (160.0g) by the volume (15.0 mi^3), which results in 10.67 g/cm^3. The density of pure lead is known to be 11.34 g/cm^3, suggesting that the sample is not pure lead but likely a different material with a lower density.
Start by writing the formula that you probably know for density D=m/V Now plug in the data that you have: 2.336 g/cm3 = m/350 cm3 so, m = 350 x 2.336 = 817.6 g
The idea is to divide the mass by the volume.
Mass and volume are extensive properties, which are dependent upon the size of the sample. A larger sample will have a greater mass and volume than a smaller sample. Density is an intensive property, which does not depend on the size of the sample. Density is a ratio of mass to volume, which does not vary with the size of the sample. The density of a larger sample will be the same as the density of a smaller sample.
A cubic centimeter of pure water at maximum density has a mass of what?
The **density** of a substance is defined as its mass per unit volume. We can calculate the density using the formula: [ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} ] Given that the sample has a volume of **50 cm³** and a mass of **135 g**, let's determine the density: [ \rho = \frac{135 , \text{g}}{50 , \text{cm³}} ] The calculated density is approximately **2.7 g/cm³**[^10^]. Now let's compare this value to known densities: **Gold**: Gold has a density of *19.3 g/cm³*⁷. The sample's density is significantly lower. **Pure Water**: The density of pure water is approximately **1 g/cm³** at 4.0°C (39.2°F) . The sample's density is higher than water. **Aluminum**: Aluminum has a density of *2.7 g/cm³*[^10^]. The sample's density matches that of aluminum. **Ocean Water**: Ocean water contains dissolved salts, which increase its density. Seawater density typically ranges from *1.02 g/cm³ to 1.03 g/cm³*. The sample's density is higher than seawater. Based on the calculated density, the sample is most likely **aluminum**.
One way of determining if a sample of gold is pure, would be to compare the density with that of real gold.
One way of determining if a sample of gold is pure, would be to compare the density with that of real gold.
You can determine if a coin is not pure silver by calculating its density using the formula density = mass/volume. Compare this calculated density to the known density of pure silver (10.5 g/cm3). If the calculated density does not match the density of pure silver, then the coin is not pure silver.
No, the density of a kilogram of iron is greater than the density of 1 gram of iron. Density is a measure of how much mass is contained in a given volume, so a kilogram of iron has much more mass in the same volume as 1 gram of iron, leading to a higher density.