To find the mass of a 3 cm cube of pine, we first calculate its volume, which is (3 \text{ cm} \times 3 \text{ cm} \times 3 \text{ cm} = 27 \text{ cm}^3). Pine has an average density of about 0.5 to 0.6 grams per cubic centimeter. Therefore, the mass of the cube would be approximately 13.5 to 16.2 grams, depending on the specific density of the pine used.
To calculate the mass of an ice cube measuring 5.80 cm on each side, first find its volume. The volume of a cube is given by ( V = s^3 ), where ( s ) is the side length. For a 5.80 cm cube, the volume is ( 5.80^3 = 195.112 , \text{cm}^3 ). Since the density of ice is approximately 0.92 g/cm³, the mass can be calculated as ( \text{mass} = \text{density} \times \text{volume} ), resulting in a mass of about 179.09 grams.
To determine if a solid cube with 6-cm sides and a mass of 270 g would float, we need to calculate its density and compare it to the density of water. The volume of the cube is (6 , \text{cm} \times 6 , \text{cm} \times 6 , \text{cm} = 216 , \text{cm}^3). The density of the cube is ( \frac{270 , \text{g}}{216 , \text{cm}^3} \approx 1.25 , \text{g/cm}^3), which is greater than the density of water (1 g/cm³). Therefore, the cube would not float.
density = mass/volume = 50g/8cm^3 = 6.25 g/cm^3
The Density of Iron is 7.874 g/cm^3. SO ...2000g/7.874g/cm^3 = 254 cm^3
6 cubic cm
The mass of a 1 cm piece of pine wood depends on the density of the pine wood. To calculate the mass, you would multiply the density of the pine wood by the volume of the 1 cm piece (which is 1 cm^3 for a cube). So, mass = density x volume.
The mass of the will depend on the density of the material the the cube is made of. If you know the density of the material in g/cm^3 you can multiply it by the volume of a cube that is 3 cm on each side (27cm^3) to find the mass.
The volume of the cube is (5.0 cm)^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass / volume = 250 g / 125 cm^3 = 2 g/cm^3. The density of the cube is 2 g/cm^3.
The volume of the cube is calculated by V = side length^3 = (1.5 cm)^3 = 3.375 cm^3. The density is then calculated by dividing mass by volume: Density = mass/volume = 1.0 g / 3.375 cm^3 = 0.296 g/cm^3.
The volume of the cube is calculated by V = s^3 = 4^3 = 64 cm^3. Divide mass by volume to get density: density = mass / volume = 512g / 64 cm^3 = 8 g/cm^3.
The volume of the cube is (3 \times 3 \times 3 = 27 , \text{cm}^3). Density is calculated by dividing mass by volume, so the density of the cube would be (27 , \text{g} \div 27 , \text{cm}^3 = 1 , \text{g/cm}^3).
The volume of the gold cube is calculated as side cubed (4 cm * 4 cm * 4 cm) = 64 cm^3. Density is mass divided by volume (1235 g / 64 cm^3 ≈ 19.3 g/cm^3). So, the density of the gold cube is approximately 19.3 g/cm^3.
To calculate the mass of an ice cube measuring 5.80 cm on each side, first find its volume. The volume of a cube is given by ( V = s^3 ), where ( s ) is the side length. For a 5.80 cm cube, the volume is ( 5.80^3 = 195.112 , \text{cm}^3 ). Since the density of ice is approximately 0.92 g/cm³, the mass can be calculated as ( \text{mass} = \text{density} \times \text{volume} ), resulting in a mass of about 179.09 grams.
The volume of the cube is calculated by V = s^3, where s is the side length (5 cm). Therefore, V = 5^3 = 125 cm^3. To find the density, divide the mass by the volume: density = mass/volume = 100 g / 125 cm^3 ≈ 0.8 g/cm^3.
density=mass divided by the volume 12g divided by 27 the volume = 0.4
Volume of cube = 6^3 = 216 cm^3 Density of cube = 270 g / 216 cm^3 = 1.25 g cm^-3 This cube would not float in water as its density is greater than the density of water at 1 g cm^3
The volume of the cube is 4cm x 4cm x 4cm = 64 cm^3. To find the density, divide the mass (50g) by the volume (64 cm^3): density = 50g / 64 cm^3 ≈ 0.78 g/cm^3.