To determine the maximum and minimum values of the objective function ( z = 3x + 5y ), we need additional constraints, typically provided in the form of inequalities. Without these constraints, the values of ( z ) can be infinitely large or small, depending on the values of ( x ) and ( y ). If specific constraints are provided, we can use methods like linear programming or graphical analysis to find the maximum and minimum values within the feasible region defined by those constraints.
To determine the maximum and minimum values of the objective function (4x + 9y), you need to specify the constraints of the problem, such as inequalities or boundaries for (x) and (y). Without these constraints, the function can theoretically increase indefinitely. If you provide a feasible region or constraints, I can help calculate the maximum and minimum values based on those limits.
the maximum or minimum value of a continuous function on a set.
A function that is continuous over a finite closed interval must have both a maximum and a minimum value on that interval, according to the Extreme Value Theorem. This theorem states that if a function is continuous on a closed interval ([a, b]), then it attains its maximum and minimum values at least once within that interval. Therefore, it is impossible for a continuous function on a finite closed interval to not have a maximum or minimum value.
There is no minimum (nor maximum) value.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
To determine the maximum and minimum values of the objective function (4x + 9y), you need to specify the constraints of the problem, such as inequalities or boundaries for (x) and (y). Without these constraints, the function can theoretically increase indefinitely. If you provide a feasible region or constraints, I can help calculate the maximum and minimum values based on those limits.
Surely, you should check the value of the function at the boundaries of the region first. Rest depends on what the function is.
the maximum or minimum value of a continuous function on a set.
The answer will depend on the ranges for x and y. If the ranges are not restricted, then C can have any value.
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
In Calculus, to find the maximum and minimum value, you first take the derivative of the function then find the zeroes or the roots of it. Once you have the roots, you can just simply plug in the x value to the original function where y is the maximum or minimum value. To know if its a maximum or minimum value, simply do your number line to check. the x and y are now your max/min points/ coordinates.
A function that is continuous over a finite closed interval must have both a maximum and a minimum value on that interval, according to the Extreme Value Theorem. This theorem states that if a function is continuous on a closed interval ([a, b]), then it attains its maximum and minimum values at least once within that interval. Therefore, it is impossible for a continuous function on a finite closed interval to not have a maximum or minimum value.
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
There is no minimum (nor maximum) value.
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.