To achieve a mean of 10 with four numbers, their total must be 40. If the median is also 10, then when the numbers are arranged in order, the average of the two middle numbers must equal 10. This can be done with combinations of numbers such as 5, 5, 15, and 15, which satisfy both conditions: their mean is 10, their median is 10, and none of the numbers are 10.
There are an infinite number of sets-of-4 that all have a mean of 12. Here are a few of them : 12, 12, 12, and 12 10, 11, 12, and 15 5, 10, 15, and 18 5, 7, 13, and 23 -12, 10, 20, and 30 1, 2, 3, and 42
The average of the numbers 8, 12, 10, 15 and 7 is 10.4. To work this out, just add up the numbers in the list and divide them by the amount of numbers in the list.
10, 20, 15, 17, 13
Range = Maximum - Minimum = 20 - 8 = 12.
The mean (average) of those numbers is 16.
If you have a plot with 5 10 15 13 and 12 the mean is where you add them all up 5+10+15+13+12=55 then, you divide by how many numbers there are in the plot 5 10 15 13 12 so divide by 5 then you have 11. do you get it?
Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a ≤ b ≤ c ≤ d ≤ e, then:median = 12 → c = 12leaving only two numbers (a, b) ≤ 12.mode = 10 → two or more numbers equal 10 (which is less than 12) → a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 → d + e = 28 → d = 13, e = 15→ {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]
Well, isn't that just a happy little group of numbers we have there? To find the mean average, you simply add up all the numbers and then divide by how many there are. So, for these numbers, you would add 18 + 12 + 10 + 10 + 25, which equals 75. Then, you divide 75 by 5 (since there are 5 numbers), giving you a mean average of 15. Happy calculating!
To achieve a mean of 10 with four numbers, their total must be 40. If the median is also 10, then when the numbers are arranged in order, the average of the two middle numbers must equal 10. This can be done with combinations of numbers such as 5, 5, 15, and 15, which satisfy both conditions: their mean is 10, their median is 10, and none of the numbers are 10.
There are an infinite number of sets-of-4 that all have a mean of 12. Here are a few of them : 12, 12, 12, and 12 10, 11, 12, and 15 5, 10, 15, and 18 5, 7, 13, and 23 -12, 10, 20, and 30 1, 2, 3, and 42
Because the mode is 5, we know at least two of the numbers are 5. Because the median is 12 and we have five numbers, we know one of them is 12. Because the range is 10 and the smallest number we know so far is 5, we'll try 15 for a fourth number. This gives us: 5, 5, 12, 15 The mean is 10, so we know the sum of all five numbers is 50. The sum of the four numbers we have so far is 5+5+12+15 = 37. Thus, the fifth number is 50-37 = 13. That gives us 5, 5, 12, 13, 15. These five numbers fit all the criteria.
The average of the numbers 8, 12, 10, 15 and 7 is 10.4. To work this out, just add up the numbers in the list and divide them by the amount of numbers in the list.
10, 20, 15, 17, 13
The mean is 15.
For the numbers 18, 16, 15, 12, 10 the LCM is: 720
15 because its an odd number whereas 6, 10 & 12 are even numbers.