Range: 5 Mean: 3
Mean: 4.2 Median: 2 Mode: 1 Range: 8
The mean is 3. The range is 4.
Mean: 4.2 Median: 2 Mode: 1 Range: 8
if you mean y=(x+2)/x, the range is all reals except y=1 If you mean y=x+2/x, the range is (-inf, -2sqrt(2)] U [2sqrt(2),+inf)
Range: 5 Mean: 3
mean= 2, mode= 1 and 3, median= 3, and range= 2
Mean: 4.2 Median: 2 Mode: 1 Range: 8
The mean is 3. The range is 4.
Mean: 4.2 Median: 2 Mode: 1 Range: 8
all the answers is 5 in this question mode is=5 media=5 mean=5
The mean, median, mode and range to this data set are:Mean = 4Median = 3Mode = 1, 2Range = 8
if you mean y=(x+2)/x, the range is all reals except y=1 If you mean y=x+2/x, the range is (-inf, -2sqrt(2)] U [2sqrt(2),+inf)
For 4 1 2 8 2 3 1 7 1 9 8:Mean = 4.18Median = 3Mode = 1Range = 8
They quick answer is YES!Here is an example.Before we begin let quickly recap what the we mean by "mean", "median", "mode" and "range":[MEAN] - The sum of all the values, divided by the total number of values.[MEDIAN] - The middle value when the data is arranged in numerical order.[MODE] - The most common value in a data set.[RANGE] - The difference between the highest and lowest values in the set.If we had the following numbers 1, 2, 2, 2, 3,The [MEAN] would be: TWO= 1+2+2+2+3/5 = 10/5 = (2)The [MEDIAN] would be: TWO= 1 2 (2) 2 3 = (2)The [MODE] would be: TWOThe most common value is (2)The [RANGE] would be: TWOrange = (highest - lowest) = (3-1) = (2)Therefore; Mean, Median, Mode and Range = (2)So the Mean, Median, Mode and Range can all be the same number![Answered by F:A:W:B:Y] - (As always, glad to help)
Mean= 5,9,6,6,1,1,8,4 = (1,1,4,5,6,6,8,9)/8 = 5 Median= (5+6)/2 =5.5 Mode= 1 ans 6. Range= (9-1) = 8
-2, 0, 1, 3, 3.