Wiki User
∙ 9y agoWant this question answered?
Be notified when an answer is posted
Range: 34 Mean: 21.71 Median: 15 Mode: 10
Mean: 13.6 Median: 15 Mode: 16, 18, 15, 9, 10
The mode is 25 and 35. The median is 30. The mean is 30.
Mean = 14 Median = 12 Mode = 12
Mean: 9 Median: 8.5 Mode: 14, 6, 8, 10, 9, 5, 7, 13
The mean is 6.6. The median is 6. There is no mode.
Range: 34 Mean: 21.71 Median: 15 Mode: 10
Mean: 13.6 Median: 15 Mode: 16, 18, 15, 9, 10
mean = 19 median = 12 mode = 12
The mode is 25 and 35. The median is 30. The mean is 30.
Mean = 14 Median = 12 Mode = 12
Mean: 11.6 Median: 12 Mode: 10, 12, 15, 16, 5 Range: 11
Range: 25 Mean: 10 Median: 11 Mode: 11, 1
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
Yes. In the set (10, 15, 20, 20, 25, 30) the mean, median and mode are all 20.
Mean: 26.33 Median: 29.5 Mode: 10, 35 Standard Deviation: 14.1515 Standard Error: 5.7773
Mean: 9 Median: 8.5 Mode: 14, 6, 8, 10, 9, 5, 7, 13