These are your 5 numbers: X X X X X the median (the middle number of a row) is 11, that means: X X 11 X X the mode (the most frequent number in a row) is 12, that means: X X 11 12 12 the mean (the average) is 10, that means: (X+X+11+12+12)/5=10 or: X+X+11+12+12=50 or: X+X=50-12-12-11 or: X+X=15 so the remaining numbers must be 15 combined, and lower then 11, that means they can be: 5 and 10 6 and 9 7 and 8 so you have 3 possible solutions: 5 10 11 12 12 6 9 11 12 12 7 8 11 12 12
11
There are an infinite number of sets-of-4 that all have a mean of 12. Here are a few of them : 12, 12, 12, and 12 10, 11, 12, and 15 5, 10, 15, and 18 5, 7, 13, and 23 -12, 10, 20, and 30 1, 2, 3, and 42
11
11
7, 10, 11, 12, 13, 14, 17
(18 + 18 + 11 + 7 + 6 + 11 + 10 + 20 + 7)/9= 12========The mean, also often called the "average", is1/9 of (18 + 18 + 11 + 7 + 6 + 11 + 10 + 20 + 7)
The average is 10... 11+11+9+7+12=50... 50/5=10
Sum = 4+8+8+11+12+14+16 = 73 Number = 7 So mean = 73/7 = 10 3/7 or 10.4258714...
115/10 = 11.5
The mean is the sum of the values divided by the number of values. In this case (12+10+19+8+2+15+1+20+6+11+3+7)/12 = 9.5.
Mean = (12+14+25+10+25+15+11)/7 = 112/7 = 16
10 7 11 12 9 13 14 11 15 16 13 17 18 15 19 20...
These are your 5 numbers: X X X X X the median (the middle number of a row) is 11, that means: X X 11 X X the mode (the most frequent number in a row) is 12, that means: X X 11 12 12 the mean (the average) is 10, that means: (X+X+11+12+12)/5=10 or: X+X+11+12+12=50 or: X+X=50-12-12-11 or: X+X=15 so the remaining numbers must be 15 combined, and lower then 11, that means they can be: 5 and 10 6 and 9 7 and 8 so you have 3 possible solutions: 5 10 11 12 12 6 9 11 12 12 7 8 11 12 12
4/5 = 0.8 5/7 ≈ 0.71 8/9 ≈ 0.89 10/12 ≈ 0.83 11/12 ≈ 0.92 Thus, the greater is 11/12. 11/12, 8/9, 10/12, 4/5, and 5/7.
11
There are an infinite number of sets-of-4 that all have a mean of 12. Here are a few of them : 12, 12, 12, and 12 10, 11, 12, and 15 5, 10, 15, and 18 5, 7, 13, and 23 -12, 10, 20, and 30 1, 2, 3, and 42