11
The mean is (8 + 7 + 10 + 14 + 1)/5 = 8
If you mean: 7/10 then they are 14/20 and 21/30
(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!
3
-1
The mean is (8 + 7 + 10 + 14 + 1)/5 = 8
If you mean 10/14, then it is 5/7 or .714. If you mean 14^10, then it is 2.89254655E11.
If you mean: 7/10 then they are 14/20 and 21/30
(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!
3
If you mean 5 and 7 then it is 10 and 14
-1
7, 10, 11, 12, 13, 14, 17
add them all up and divide by 2 ! 7+14+10+14+29+16+15=? ?/2=? Answer:52.5->53
6, 14, 7, 13, 10
10/14 > 3/710/14 > 3/710/14 > 3/710/14 > 3/7
5/7 - 7/14 becomes: 10/14 - 7/14. Then subtract across to get the final answer: 3/14. 5/7 became 10/14 by finding the lowest common denominator which is 14. Then you figure 7 goes into 14 two times, and 2x5 = 10 therefore 5/7 becomes 10/14.