11
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
11 & 14
6, 10, 11, 12, 14, 14, 15, 22 mean: 13 median: 13 mode: 14 range: 16
The integers are -14, -12 and -10.
11
How about the integers of : 10 11 12 13 14 15 ..... to infinity
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
11 & 14
(-10) + (-7) + (-14) = -31
6, 10, 11, 12, 14, 14, 15, 22 mean: 13 median: 13 mode: 14 range: 16
The integers are -14, -12 and -10.
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
-10 and -14
14
BCD code isn't valid for these integers , 10 , 11 , 12 , 13 , 14 i.e if these integers ae converted to binary code they 'd be called wrong BCD
The integers are -14, -12 and -10.