-1
11
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
11 & 14
The integers are -14, -12 and -10.
6, 10, 11, 12, 14, 14, 15, 22 mean: 13 median: 13 mode: 14 range: 16
11
How about the integers of : 10 11 12 13 14 15 ..... to infinity
14-2 = 12 12 integers. 2 3 4 5 6 7 8 9 10 11 12 13
11 & 14
(-10) + (-7) + (-14) = -31
The integers are -14, -12 and -10.
6, 10, 11, 12, 14, 14, 15, 22 mean: 13 median: 13 mode: 14 range: 16
-10 and -14
It's an even number, so it can't be expressed as the sum of two consecutive integers. You can however do: three consecutive integers: 41 + 42 + 43 four consecutive integers: 30 + 31 + 32 + 33 nine consecutive integers: 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18. twelve consecutive integers: 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16
14
BCD code isn't valid for these integers , 10 , 11 , 12 , 13 , 14 i.e if these integers ae converted to binary code they 'd be called wrong BCD
To find the mean of the numbers 12, 14, 25, 10, 25, 15, and 11, first, sum them: 12 + 14 + 25 + 10 + 25 + 15 + 11 = 112. Then, divide the total by the number of values (7): 112 ÷ 7 = 16. Therefore, the mean is 16.