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8

mean = (9+3+8+10+12+6)/6

= 48/6

= 8

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βˆ™ 11y ago
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Q: What is the mean of the numbers 9 3 8 10 12 6?
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Related questions

What are 5 numbers with a mean of 12 and a range of 3?

(10, 12, 12, 13, 13)


How do uu find the mean?

To find the mean you first have to add up all the numbers then you divide it by how many numbers you have and you got the mean. Example: 12+13+5=30 30/3=10 10 is the mean


How many sets of 3 numbers can be made out of 12 different numbers?

You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.


What is the average mean for -20 -20 -10 10 15 20 30 25 20 10 8 -20?

Add up all the numbers together and then divide by 12 to find the average mean:- 68/12 = 17/3 or as 5 and 2/3


What sort of numbers are 3 6 10 and 12?

They are all positive numbers.


What are 4 different numbers who have a mean of 12?

There are an infinite number of sets-of-4 that all have a mean of 12. Here are a few of them : 12, 12, 12, and 12 10, 11, 12, and 15 5, 10, 15, and 18 5, 7, 13, and 23 -12, 10, 20, and 30 1, 2, 3, and 42


What 3 numbers have a mean of 30?

10


How do you get 24 with the numbers 2 2 3 7?

3+7=10 10+2=12 12*2=24


What is the average of these numbers 6 12 10 4 3?

(6 + 12 + 10 + 4 + 3) ÷ 5 = 7 Therefore, 7 is the average of the five numbers given in the question.


What is the mean of the set of numbers What is the mean of the set of numbers -12 -4 3 7 11?

2


How can you find the mean number?

Add all the numbers up and divide by how many there are... Example: 10,11,12 add them up: 10+11+12= 33 then divide by how many numbers there are... 3 33/3 = 11


What is a mixed number between 3 and 4 that has a produce between 9 and 12?

By "produce" do you mean "product". If so, you need two numbers to form a produce. You could use 3 1/10 and 3 2/10. They are mixed numbers between 3 and 4 whose product is between 9 and 12. There are infinitely many other answers to this question.