The meanings are the same but getting the answers use different rules. Ex:
1. None complex-(x+y)^2=xx+yy+2xy and is a family of parallel lines.
2. Complex-(x+iy)^2 Now notice the "i operator" and how it is used in the computation. (x+iy)(x+iy)=xx+i2xy+iiyy. Now i=(-1)^.5, so ii=-1 and so we have
xx-yy+i2xy. If we graph this out, we get families of parabolas at right angles to
each other. The (xx-yy) are the real and at right angles to the i2xy, the imaginaries.
Maybe somebody else can tackle the roots.
The complex roots of an equation are the complex numbers that are solutions to the equation.
The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.
They are called real numbers. Negative square roots must be complex numbers.
There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.
Two of the four roots are 1.8212 and -1.8212 (approx). The other two roots are complex numbers.
The complex roots of an equation are the complex numbers that are solutions to the equation.
Complex numbers are the square roots of negative numbers. i.e. root -1 = i
The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.
They are called real numbers. Negative square roots must be complex numbers.
I posted an answer about cube roots of complex numbers. The same info can be applied to square roots. (see related links)
Because in real numbers they are not defined.
The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.
There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.
Negative numbers have no real square roots. In terms of complex numbers, the square roots of 43 are +j6.5574 (rounded) and -j6.5574 (rounded)
5, Using complex numbers you will always get 5 roots.
Two of the four roots are 1.8212 and -1.8212 (approx). The other two roots are complex numbers.
Square roots of negative numbers are complex, meaning that they carry a 'real' and an 'imaginary' part. Here the real part is approximately 5.8309518948453 and the imaginary part is i.