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The meanings are the same but getting the answers use different rules. Ex:

1. None complex-(x+y)^2=xx+yy+2xy and is a family of parallel lines.

2. Complex-(x+iy)^2 Now notice the "i operator" and how it is used in the computation. (x+iy)(x+iy)=xx+i2xy+iiyy. Now i=(-1)^.5, so ii=-1 and so we have

xx-yy+i2xy. If we graph this out, we get families of parabolas at right angles to

each other. The (xx-yy) are the real and at right angles to the i2xy, the imaginaries.

Maybe somebody else can tackle the roots.

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Related questions

What are complex root?

The complex roots of an equation are the complex numbers that are solutions to the equation.


Where you use complex number?

Complex numbers are the square roots of negative numbers. i.e. root -1 = i


How do you simplify fourth roots?

The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.


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They are called real numbers. Negative square roots must be complex numbers.


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I posted an answer about cube roots of complex numbers. The same info can be applied to square roots. (see related links)


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Because in real numbers they are not defined.


What are the compex roots in mathematics?

The complex roots of an equation is any solution to that equation which cannot be expressed in terms of real numbers. For example, the equation 0 = x² + 5 does not have any solution in real numbers. But in complex numbers, it has solutions.


What the square roots of -256?

There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.


What is the square root of -43?

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What is the square root of -34?

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