The meanings are the same but getting the answers use different rules. Ex:
1. None complex-(x+y)^2=xx+yy+2xy and is a family of parallel lines.
2. Complex-(x+iy)^2 Now notice the "i operator" and how it is used in the computation. (x+iy)(x+iy)=xx+i2xy+iiyy. Now i=(-1)^.5, so ii=-1 and so we have
xx-yy+i2xy. If we graph this out, we get families of parabolas at right angles to
each other. The (xx-yy) are the real and at right angles to the i2xy, the imaginaries.
Maybe somebody else can tackle the roots.
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The complex roots of an equation are the complex numbers that are solutions to the equation.
They are called real numbers. Negative square roots must be complex numbers.
The answer will depend on the form of the fourth root. Positive real numbers will have two fourth roots which are real and two that are complex. Complex numbers will have four complex roots. However, none of these can be "simplified" in the normal sense of the term.
There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.
Two of the four roots are 1.8212 and -1.8212 (approx). The other two roots are complex numbers.