You've conveniently neglected to say where these three angles are found.
Perhaps they are the interior angles of a plane triangle ? If that's true, then
the third angle is 90 degrees. But we can't really tell from the information gven
in the question.
A whole angle is 360 degrees so the measure of a 35% angle is 126 degrees. The complement (not compliment) of this angle would have a measure of 90 - 126 = minus 36 degrees.
36 and 54 degrees.
Providing that it's a regular decagon then each exterior angle will measure 36 degrees
Each exterior angle measures 36 degrees Each interior angle measures 144 degrees
360/10 = 36 degrees
If that's a triangle, the third angle is 90 degrees.
A whole angle is 360 degrees so the measure of a 35% angle is 126 degrees. The complement (not compliment) of this angle would have a measure of 90 - 126 = minus 36 degrees.
36 and 54 degrees.
Providing that it's a regular decagon then each exterior angle will measure 36 degrees
360/36 = 10 degrees
Let first angle be "A", second angle "B" and third angle "C", then C = B - 5 A = 3B + 5 But "A" + "B" + "C" must rqual 180 Substitue for "A" and "C" and we get 3B + 5 + B + B - 5 = 180 5B = 180 or B = 36 degrees Therefore A = 3 x 36 + 5 = 113 degrees and C = 31 degrees Verification: A + B + C = 113 + 36 + 31 = 180
Providing that it's a regular decagon then each exterior angle will measure 36 degrees
36 degrees
170 degrees
54 degrees
Each exterior angle measures 10 degrees Each interior angle measures 170 degrees
Each exterior angle measures 36 degrees Each interior angle measures 144 degrees