Let first angle be "A", second angle "B" and third angle "C", then
C = B - 5
A = 3B + 5
But "A" + "B" + "C" must rqual 180
Substitue for "A" and "C" and we get
3B + 5 + B + B - 5 = 180
5B = 180 or B = 36 degrees
Therefore A = 3 x 36 + 5 = 113 degrees and C = 31 degrees
Verification: A + B + C = 113 + 36 + 31 = 180
15°
The angles are: 150+30 = 180 degrees
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Five of the six exterior angle measures of a nonregular hexagon measure 55, 60, 69, 57, and 57. what is the measure of the unterior angle adjacent to the sixth exterior angles?
74
15°
150o
go off
The angles are: 150+30 = 180 degrees
The degree measure of five fourths of a right angle is 112.5 degrees
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
Complementary angles add up to 90 degrees. If one angle is five times the measure of the other, you can express their measurements as 5x and x. The original angle is x degrees and its complement is 5x degrees. Set the sum of the two angles equal to 90 and solve for x. 5x + x = 90 6x = 90 x = 15 The angle is 15 degrees. Its complement is 5(15) = 75 degrees. 75 + 15 = 90.
Use a "three four five" triangle. Having one leg measure exactly three inches, the other leg exactly four inches, and the hypotenuse measure exactly five inches will yield a ninety degree angle. If you are drawing out the triangle, it may be easier to measure a three inch line using a straightedge and then use a compass to find the point of intersection for the other leg and the hypotenuse.
150 degrees
Sum of all three angles is 180 degrees. p = 36 so q+r = 180-36 = 144 degrees. Now, q = 5r so 144 = q+r = 5r+r = 6r so r = 144/6 = 24 and then q = 5r = 5*24=120 Answer: q = 120 deg, r = 24 deg