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Two angles are supplementary.The second angle has a mesaure five times that of the first Find the measure of the angle?
Suppose the angle is x then the second is 5x. The two angles are supplementary so x + 5x = 180 or 6x = 180 so that x = 30 degrees.
How do you find the perimeter of a triangle with sides like 2x and 5x and 6x?
To find the perimeter of a triangle you have to add up all the sides. So to find the perimeter of this triangle you just add 2x+5x+6x=13x. To find the actual perimeter you would have to know what x equals
Find all degree solutions 2sin2 6x plus 3sin6x plus 1 equals 0?
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
How do you state the degree of a polynomials?
find the number with the highest exponent, that exponent is the degree. for example, 2x to the 3rd power + 6x to the 2nd power the degree is 3
The ratio of the measure of a supplement angle to a complement of a same angle is 7 to 1 what are the measures of the 3 angles?
(180 - x) / (90 - x) = 7Multiply each side by 7:180 - x = 630 - 7xSubtract 180 from each side:- x = 450 - 7xAdd 7x to each side:6x = 450Divide each side by 6:x = 75The angle is 75 degrees.Its supplement is 105 degrees.Its complement is 15 degrees.Check: 105/15 = 7 yay!
The largest angle of a triangle is 6 times the smallest angle and 3 times the other angle Find the measure of the smallest angle?
x + 2x = 6x = 180 9x = 180 9x/9 = 180/9 x = 20....theres you answer
what is 6x what is 30?
6x what = 180
What is the measure of each base angle of an isosceles triangle if the vertex measures 6X plus 8 and 9X-25?
If the two expressions given for the vertex angle are to be the same number, 6x + 8 = 9x -25; then 3x = 25 + 8 = 33 and x = 11. Therefore, the vertex angle is 6(11) + 8 = 74. The two base angles of an isosceles triangle must be the same and the three angles of the triangle must sum to 180. Therefore, calling the unknown base angle y, 2y + 74 = 180, or y equals 53.
In parallelogram ABCD if angle A equals 5x plus 30 and angle D equals x find angle c?
In parallelogram ABCD, angle A and angle D are adjacent or consecutive angles and are supplementary, meaning the sum of their measures is equal to 180 degrees. Angles A and C are opposite angles and have the same measure. These are some important properties of parallelograms. So to find the measure of angle C, you first have to find the measure of angle A. You can do that with a little algebra. First, set the expressions for the measures of angles A and D equal to 180 and solve for x. Then plug that value for x into the expression for the measure of angle A, which is the same as the measure for angle C. 5x + 30 + x = 180 6x + 30 = 180 6x = 150 x = 25 Therefore, 5x + 30 = 5(25) + 30 = 125 + 30 = 155 The measure of angle C is 155.
Two angles are supplementary.The second angle has a mesaure five times that of the first Find the measure of the angle?
Suppose the angle is x then the second is 5x. The two angles are supplementary so x + 5x = 180 or 6x = 180 so that x = 30 degrees.
Angles X and Y are supplementary If the measure of angle X equals 2x plus 4 and the measure of angle Y equals 4x plus 20 then what is the measure of each angle and why?
X = 180 - Y so 180 - Y = 2x + 4 and Y = 4x + 20 so 180 - 4x - 20 = 2x + 4 therefore 6x = 156 so x = 26 making Angle X = 56o and Angle Y = 124o
How do you find the perimeter of a triangle with sides like 2x and 5x and 6x?
To find the perimeter of a triangle you have to add up all the sides. So to find the perimeter of this triangle you just add 2x+5x+6x=13x. To find the actual perimeter you would have to know what x equals
If the measure of one angle is 2x and the measure of its complement is 6x what is the value of x?
11.25
Find all degree solutions 2sin2 6x plus 3sin6x plus 1 equals 0?
2sin2(6x) + 3sin(6x) + 1 = 0 Solving the quadratic, sin(6x) = -1 or sin (6x) = -0.5 sin(6x) = -1 => 6x = 45+60n degrees for integer n sin(6x) = -0.5 => 6x = 35+60n or 55+60n degrees for integer n.
How do you get 180 by 6 6 6 6?
The easiest way would be 6x(6x6-6)
In triangle mnp the measure of angle m is 24 the measure of angle n is five times the measure of angle p find the measure of angle n?
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
Find the perimeter of the triangle with sides of length x 5x and 6x-3?
Find the perimeter of the triangle with sides of length x, 5x and 6-3x?
