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# What is the measure of a side of a square whose diagonal is 4 inches longer than its side?

Updated: 10/25/2022

Wiki User

13y ago

Let a side of the square be x and its diagonal x+4:-

Using Pythagoras' theorem:

2x2 = (x+4)2

2x2 = x2+8x+16

Subtract x2+8x+16 from both sides:

x2-8x-16 = 0

Using the quadratic equation formula to solve the above gives x a positive value of 9.65685425

Therefore the sides are 9.65685425 inches and the diagonal is 13.65685425 inches.

Check: 2*9.656854252 = 186.509668 and the square root of this is 13.65685425

Wiki User

13y ago

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Q: What is the measure of a side of a square whose diagonal is 4 inches longer than its side?
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