43
The median is 78.
The average is 70.
the median is 785
I guess you mean: What is the median of the numbers 71, 67, 67, 72, 76, 73, 68, 72, 72? (because adding the numbers would yield a single number). The median is the middle number when the numbers are listed in order. Listing in order: 71, 67, 67, 72, 76, 73, 68, 72, 72 ⇒ 67, 67, 68, 71, 72, 72, 72, 73, 76 There are 9 numbers, so the middle number is the 5th one which is 72. If there had been an even number of numbers, there is no middle one so the median is the mean average of the middle two. Example: If there had been no 76, so the list contained: 67, 67, 68, 71, 72, 72, 72, 73 then there would be 8 numbers, so the median would be the mean average of the 4th and 5th numbers, namely: (71 + 72) ÷ 2 = 71.5
71 is the median of those numbers.
70
64 64 64 65 65 65 65 67 67 68 68 70 70 72 73 76 79 80. NB Place the numbers in RANK order. In this case it is already done #1 MODE ; is the term that occurs most frequently. In this case it is '65' , as there are four lots of '65' #2 MEDIAN ; is the term that occurs at the ABSOLUTE middle of the ranked order. Since there are eighteen terms, there is no absolute middle term. So we take the two middle terms that have the same number of terms to their side, that is terms nine & ten. They are 67 & 68. We then add these two together and halve the result. Hence (67 + 68) / 2 = 67.5. This is the median term. #3 MEAN ; is the sum of all the terms, which is the divided by the number of terms. Hence (64+64+64+65+65+65+65+67+67+68+68+70+70+72+73+76+79+80)/18 = 69' NB Another way of calculating the mean is ((3x64)+(4x65)+(2x67)+(2x68)+(2x70)+72+73+76+79+80)/18 = 69 NNB The word 'average' is casually used in the non-mathematical world, but the correct term is MEAN.
It is: 69
It is 68, the number in the middle when they are arranged in order.
step 1. arrange the numbers in ascending order (from low to high) as follows. was: 64 80 64 70 76 79 67 72 65 73 68 65 67 65 70 62 67 68 65 64 now: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 step 2. count the number of the numbers above, or assign an index as follows. string: 62 64 64 64 65 65 65 65 67 67 67 68 68 70 70 72 73 76 79 80 index: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 so the count is 20. The mode is the number most frequently observed. The mode is 65, which occurs four times. The median is the number in the middle. In this case, the 10th and 11th numbers both qualify for consideration. We take the average of the two numbers. The median is therefore 67. Alternate methods: 1) Use Microsoft Excel statistical functions of =mode() and =median() 2) Draw a bar graph with the horizontal axis of integers from 62 to 80. The y-axis is the frequency observed for that specific x value. For example, the frequency for 62 is one. The frequency for 63 is zero, and so on. The mode is the bar with the highest count. The median is not so obvious from a bar graph, unless the distribution is symmetric. Need some manual counting.
43
65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80
The median is 78.
65, 66 67 68 and 69 can all be numbers to be rounded to 70.
First of all place the numbers in rank order. Hence 46,57,68,72,72,93. RANGE; is the difference between the highest and lowest numbers, which is 93-46 = 47 MEDIAN: is the absolute mid-point. Since there is no absolute mid-point, we take the two middle numbers , add them and divide by '2'. Hence. ( 68+72)/2 = 70 MODE: is the term that occurs most frequently. In this case '72'. as there are two of them , but only one each of the other terms. MEAN; Add all the terms and divide by the number of terms. (46+57+68+72+72+93) / 6 = 408/6 = 68
The range is 72 minus 66 = 6