The median of an even number of data is the average of the two data closest to the center of the sorted list.
The sorted list is 43, 47, 49, 50, 50, 52, 52, 52, 58 & 60. The two numbers closest to the center of the list are 50 and 52, the average of which is 51.
The median is 49.
49
31, 43 and 47 are prime.
49 is.
49C6 = 49!/[(49 - 6)!6!] = 49!/(43!6!) = (49*48*47*46*45*44*43!)/(43!*6*5*4*3*2*1) = 49*47*46*3*44 = 13,983,816 or 49C6 = 49*48*47*46*45*44/6*5*4*3*2*1 = 13,983,816
The median is 49.
49
It is: 49
To find the median of a set of numbers, you first need to arrange the numbers in either ascending or descending order. Once the numbers are arranged, the median is the middle number in the set. In this case, when the numbers are arranged in ascending order, the set becomes 43, 44, 45, 47, 48, 49, 49, 52, 53. Since there are 9 numbers in total, the middle number is the 5th number, which is 48. Therefore, the median of the given set of numbers is 48.
31, 43 and 47 are prime.
The GCF is 1.
43 45 47 49
49 is.
49C6 = 49!/[(49 - 6)!6!] = 49!/(43!6!) = (49*48*47*46*45*44*43!)/(43!*6*5*4*3*2*1) = 49*47*46*3*44 = 13,983,816 or 49C6 = 49*48*47*46*45*44/6*5*4*3*2*1 = 13,983,816
41 43 47.
41, 43, and 47
41, 43, 47