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What is the total amount of 2 number combinations for numbers 1-36?
454
How many combinations of 6 numbers are there in 44 numbers?
Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.
How many combinations of five numbers are there?
The number of combinations of five numbers depends on the total number of available numbers to choose from, as well as whether the order of selection matters. If you have a specific set of numbers (for example, 1 to n), you can calculate the combinations using the formula for combinations: ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of numbers and ( r ) is the number of selections (in this case, 5). If no total is specified, the answer cannot be determined.
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many 3 number combinations are there in the numbers 1 - 20?
Well, honey, there are 20 numbers to choose from for the first digit, 19 for the second, and 18 for the third. So, multiply those together and you get a total of 6,840 possible 3-number combinations. Math can be a real party pooper, but hey, that's the answer for ya!
What is the total amount of 2 number combinations for numbers 1-36?
454
How many combinations of 6 numbers are there in 44 numbers?
Just use combinations formula. nCr, where n=44, r=6. Plug it into the calculator or use the formula, nCr = n!/[r!(n-r)!] And you should get 7059052 as the number of combinations.
How many 4 number combinations are there with 16 numbers?
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
How many combinations of five numbers are there?
The number of combinations of five numbers depends on the total number of available numbers to choose from, as well as whether the order of selection matters. If you have a specific set of numbers (for example, 1 to n), you can calculate the combinations using the formula for combinations: ( \binom{n}{r} = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of numbers and ( r ) is the number of selections (in this case, 5). If no total is specified, the answer cannot be determined.
How many 5 number combinations are there for 59 numbers?
Oh, what a lovely question! To find the number of 5-number combinations from 59 numbers, we can use a formula called combinations. It's like mixing colors on your palette! The formula is nCr = n! / r!(n-r)!, where n is the total numbers (59) and r is the number of selections (5). So, for 59 numbers choosing 5 at a time, there are 5,006,386 unique combinations waiting to be discovered! Just imagine all the beautiful possibilities that can come from those combinations.
If using numbers 1 thru 49 how many 6 digit combinations can be made?
Using the formula n!/r!(n-r)! where n is the number of possible numbers and r is the number of numbers chosen, there are 13983816 combinations of six numbers between 1 and 49 inclusive.
How many 3 number combinations are there in the numbers 1 - 20?
Well, honey, there are 20 numbers to choose from for the first digit, 19 for the second, and 18 for the third. So, multiply those together and you get a total of 6,840 possible 3-number combinations. Math can be a real party pooper, but hey, that's the answer for ya!
How many 7 number combinations from 8 numbers?
To calculate the number of 7-number combinations from 8 numbers, you can use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 8 (total numbers) and r = 7 (numbers chosen). Plugging these values into the formula, you get 8C7 = 8! / 7!(8-7)! = 8 ways. Therefore, there are 8 different combinations of 7 numbers that can be chosen from a set of 8 numbers.
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many combinations are there in 21 numbers?
Oh, what a happy little question! To find the number of combinations in 21 numbers, we can use a formula called combinations. It's like mixing colors on your palette - each combination is unique and beautiful in its own way. So, for 21 numbers, the number of combinations would be calculated using the formula nCr = n! / r!(n-r)!. Just remember, there's no mistakes, just happy little accidents in math!
How many 4 digit combinations can you get from numbers 1226?
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
How many 4 number combinations are there in the numbers1 to 20?
To calculate the number of 4-number combinations from 1 to 20, we can use the formula for combinations, which is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to choose. In this case, n = 20 and r = 4. Plugging these values into the formula, we get 20C4 = 20! / (4!(20-4)!) = 4845. Therefore, there are 4845 different 4-number combinations possible from the numbers 1 to 20.
